We can calculate the width of the rectangle patio with pythagorean theorem:
![\begin{gathered} \text{Base of triangle=15-12=3} \\ c^2=a^2+b^2 \\ 5^2=3^2+b^2 \\ b=\sqrt[]{25-9} \\ b=\sqrt[]{16} \\ b=4 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Ctext%7BBase%20of%20triangle%3D15-12%3D3%7D%20%5C%5C%20c%5E2%3Da%5E2%2Bb%5E2%20%5C%5C%205%5E2%3D3%5E2%2Bb%5E2%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B25-9%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B16%7D%20%5C%5C%20b%3D4%20%5Cend%7Bgathered%7D)
Then, she need to put trim on the edge of the floow of the patio that is wood planks and DOES NOT share and edge with the brick part:

Loretta need to put 28 feet of trim.
I'm not sure if this is right, but I multiplied 115 by 4 and got 460- Try that? ;^;
Let L be the length of the deck
= 42 feet
Let W be the width of the deck =
28 feet
A = LxW
A = 42 feet x 28 feet
A = 1176 square feet
Remaining area to be painted =
1176 square feet – 350 square feet
<span>Remaining area to be painted = 826 square feet</span>
Answer:
a=88
b=82
Step-by-step explanation:
perimeter=2(l+w)
302=2(l+63)
302=2l+126
2l=176
l=88
A=l×w
8118=99×82
w=82