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Law Incorporation [45]
3 years ago
12

Can FLVS see what website i copy and pasted from?

Mathematics
1 answer:
Zepler [3.9K]3 years ago
4 0

Answer:

Hi! They most likely ran your answer through a copywrite website or just googled your answer and that's how they found out you cheated. Therefore, they probably know what site you copied the answer from. Sorry hun!

If it was a math problem then was it just an equation with the answer in number form? If so, then she probably could only tell what you copy and pasted. So she'll most likely be able to see that you didn't just copy and paste a division symbol...

In conclusion, either way she knows you cheated. Next time, re- word as much as you can and type everything out yourself! Good luck hun!

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James bought a plant that was 3 inches tall. Each week the plant
sattari [20]

Answer:

1.5 inches/ week

Step-by-step explanation

Given

Height of he plant = 3in

If the plant grows by 2in every week

The rate of change = Height of plant/weekly increase

The rate of change = 3/2 = 1.5 inches/ week

6 0
3 years ago
Help please!! Stuck on this question!! ∠ABC is adjacent to ∠CBD. If the m∠ABC=4x+23, m∠CBD=6x+7, and m∠ABD=130°, what is the mea
Ulleksa [173]

Answer:

63 degrees

Step-by-step explanation:

add 4x + 23 and 6x + 7, then equal that to 130. When you find x, plug it into 4x+23 and get 63.

3 0
3 years ago
If f(x) = e^[3ln(x^2)], then f'(x) = ?
kherson [118]
You might need to give out the choices, if there are any. thanks for asking.
8 0
3 years ago
Read 2 more answers
Can someone help? It’s about 2 column proofs
Gwar [14]

Step-by-step explanation:

1. AB = BC (B is the midpoint of AC)

2. DE = EF (E is the midpoint of DF)

3. EB is common

4. ∠ABE = ∠CBE; ∠BED = ∠BEF (EB⊥AC, EB⊥DF)

5. ΔDEB ≅ ΔFEB (RHS)

6. DB = FB (corresponding ∠s of ≅ Δs)

7. ∠EFB = ∠CBF; ∠EDB = ∠ABD (alternate interior angles, AC║DF)

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4 0
3 years ago
The number of girl child per family was recorded for 1000 families with 3 children. The data obtained was as follows: [2] Number
ira [324]

Answer:

a.\ Probability = 0.426

b.\ Probability = 0.574

Step-by-step explanation:

Given

Total\ Families = 1000

Number of Girls :      0 ---->  1 -----> 2   ------->3

Number of Families: 112 -> 314 --> 382 ---> 192

Solving (a): At most one girl

From the table, the number of families with at most one girl is: 112 + 314

i.e.

Number of Girls :      0 ---->  1

Number of Families: 112 -> 314

So, we have:

At\ Most\ One\ Girl = 112 + 314

At\ Most\ One\ Girl = 426

The probability is then calculated as:

Probability = \frac{At\ Most\ One\ Girl}{Total}

Probability = \frac{426}{1000}

Probability = 0.426

Solving (b): More girls

From the table, the number of families with more girl is: 382 + 192

i.e.

Number of Girls :      -----> 2   ------->3

Number of Families: --> 382 ---> 192

So, we have:

More\ Girls = 382 + 192

More\ Girls = 574

The probability is then calculated as:

Probability = \frac{More\ Girls}{Total}

Probability = \frac{574}{1000}

Probability = 0.574

4 0
2 years ago
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