In a game the player wins if he rolls a 6 on a number cube .if the number cube is rolled 18 times then what is the reasonable
1 answer:
<h2>Answer:</h2>
Prediction for the number of unsuccessful rolls is 15.
<h2>Step-by-step explanation:</h2>There is chance of rolling number 6 on the cube. If we want to find out what is the prediction for rolling number 6 in 18 rolls, we need to multiply
which is 3. So if we roll a cube 18 times, we will probably got number 6 three times. When we subtract 3 from 18 (18-3), we get 15. That is the answer to your question.
I hope I helped you. I will be really happy, If you mark my answer as the brainliest.Your David
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Answer:
a) Number of projects in the first year = 90
b) Earnings in the twelfth year = $116500
Total money earned in 12 years = $969000
Step-by-step explanation:
Given that:
Number of projects done in fourth year = 129
Number of projects done in tenth year = 207
There is a fixed increase every year.
a) To find:
Number of projects done in the first year.
This problem is nothing but a case of arithmetic progression.
Let the first term i.e. number of projects done in first year =
Given that:
Formula for term of an Arithmetic Progression is given as:
Where will represent the number of projects increased every year.
and is the year number.
Subtracting (2) from (1):
By equation (1):
<em>Number of projects in the first year = 90</em>
<em></em>
<em>b) </em>
Number of projects in the twelfth year =
Each project pays $500
Earnings in the twelfth year = 233 500 = $116500
Sum of an AP is given as:
It gives us the total number of projects done in 12 years = 1938
Total money earned in 12 years = 500 1938 = $969000
We have that
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure
csc ∅=13/12
sec ∅=-13/5
cot ∅=-5/12
we know that
csc ∅=1/sin ∅
sin ∅=1/ csc ∅------> sin ∅=12/13
sec ∅=-13/5
sec ∅=1/cos ∅
cos ∅=1/sec ∅------> cos ∅=-5/13
sin ∅ is positive and cos ∅ is negative
so
∅ belong to the II quadrant
therefore
<span>the coordinates of point (x,y) on the terminal ray of angle theta are
</span>x=-5
y=12
the answer is
point (-5,12)
see the attached figure