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3 years ago

What form of a quadratic function would be graphed having the vertex at the same point as the y-intercept

1 answer:

5 0

The functions would be in the form of ax2+c. The axis of symmetry would be the y-axis , or x=0 , because b would be zero. Likewise, the y-intercept is not important, as any value of c will still yield a vertex at the y-intercept.

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PLZ help!<br> I feel dumb asking, but I need help, math is quite hard.

ehidna [41]

Answer:

slope= 3/4

y=mx+b

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Find out if the 3 positions are on the same line or not (3,2,0) (1, -1,2) (5,5, 2)

sattari [20]

Answer:

The three positions are not on the same line.

Step-by-step explanation:

We have three points: A:(3,2,0), B:(1,-1,2) and C:(5,5,2).

Let's build a vector that goes from one point to another; that vector will be the director of a line (if we draw a vector that goes from A to B, that vector will be the direction of the line that pass by A and B because it does not change). In order to build that vector, let's subtract B from A:

$A-B=(3,2,0)-(1,-1,2)=(2,3,-2)$

The equation of a line is:

$p=p_0+rt$

Where p is every singular point of the line, $p_0$ is a particular point of the line (any that we are sure that it is on the line), r is the director vector and t is the independent variable.

Now we have the director vector: (2,3,-2), and we can verify that A and B are on the line:

$p=p_0+(2,3,-2)t$

Because there is a value for t that satisfies both A and B: If we do $p_0=(3,2,0)$ and t=0, we are going to obtain the point p=A; and if we do t=-1, we are going to obtain p=B. Let's see that:

$p=(3,2,0)+(2,3,-2)*0=(3,2,0)\\p=A\\p=(3,2,0)+(2,3,-2)*-1=(1,-1,2)\\p=B\\$

If C is also in the same line, C must accomplish the equation: $p=(3,2,0)+(2,3,-2)t$ , so:

$C=(5,5,2)=(3,2,0)+(2,3,-2)t$

Let's simplify the equation writing the parametric equation, which is just to write the equation for each dimension:

$5=3+2t\\5=2-3t\\2=-2t\\$

You can verify that there is not a value of t that satisfies all three equations, so, the point C is not on the same line as A and B; which means that A, B and C are not on the same line.

8 0

3 years ago

Turn 1 1/5 to improper fraction

Alex17521 [72]

Answer:

Explanation:

Step 1

Multiply the denominator by the whole number

5 × 1 = 5

Step 2

Add the answer from Step 1 to the numerator

5 + 1 = 6

Step 3

Write answer from Step 2 over the denominator

<h2><u>6/5</u></h2><h2><u></u></h2><h2><u>I hope this answer helps you out! Brainliest would be appreciated.</u></h2>

4 0

3 years ago

Triangle BCD is equivalent AG=1.find the perimeter of BCD

Ymorist [56]

AG=1 => BG=3 => CG=sqrt3 => CD = 2sqrt3 => perimeter = 3*CD= 6sqrt3

4 0

3 years ago

Determine the domain and range of the function f(x)= 3x+2. Also, state the intervals where the function f(x)= 3x+ 2 is increasin

aev [14]

Answer:

Increasing on it's domain $(-\infty,\infty)$ because the slope is positive.

The domain and range are both all real numbers, also known as

$(-\infty,\infty)$ .

Step-by-step explanation:

All domain really means is what numbers can you plug in and you get number back from your function.

I should be able to plug in any number into 3x+2 and result in a number. There are no restrictions for x on 3x+2.

The domain is all real numbers.

In interval notation that is $(-\infty,\infty)$ .

Now the range is the set of numbers that get hit by y=3x+2.

Well y=3x+2 is a linear function that is increasing. I know it is increasing because the slope is positive 3. I wrote out the positive part because that is the item you focus on in a linear equation to determine if is increasing or decreasing.

If slope is positive, then the line is increasing.

If slope is negative, then the line is decreasing.

So y=3x+2 hits all values of y because it is increasing forever. The range is all real numbers. In interval notation that is $(-\infty,\infty)$ .

3 0

3 years ago