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faltersainse [42]
3 years ago
12

What form of a quadratic function would be graphed having the vertex at the same point as the y-intercept

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
5 0
The functions would be in the form of ax2+c. The axis of symmetry would be the y-axis , or x=0 , because b would be zero. Likewise, the y-intercept is not important, as any value of c will still yield a vertex at the y-intercept. 
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3x+3y=27<br> 3x-3y= -11<br> using elimination
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3x + 3y = 27
3x - 3y = -11
------------------add
6x = 16
x = 16/6 which reduces to 8/3

3x + 3y = 27
3(8/3) + 3y = 27
8 + 3y = 27
3y = 27 - 8
3y = 19
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</span>
which means that the two halves are equal to 5y+13=5*2.25+13=24.25

and FG is double the lenght:

24.25*2=49


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