Δ = 1 + 4*20 = 81
x' = (-1 + 9)/2 = 4
x'' = (-1 - 9)/2 = -5
4² + 4 - 20 = 0
(-5)² - 5 - 20 = 0
Ok !
Best Answer: 2 LiCl = 2 Li + Cl2
mass Li = 56.8 mL x 0.534 g/mL=30.3 g
moles Li = 30.3 g / 6.941 g/mol=4.37
the ratio between Li and LiCl is 2 : 2 ( or 1 : 1)
moles LiCl required = 4.37
mass LiCl = 4.37 mol x 42.394 g/mol=185.3 g
Cu + 2 AgNO3 = Cu/NO3)2 + 2 Ag
the ratio between Cu and AgNO3 is 1 : 2
moles AgNO3 required = 4.2 x 2 = 8.4 : but we have only 6.3 moles of AgNO3 so AgNO3 is the limiting reactant
moles Cu reacted = 6.3 / 2 = 3.15
moles Cu in excess = 4.2 - 3.15 =1.05
N2 + 3 H2 = 2 NH3
moles N2 = 42.5 g / 28.0134 g/mol=1.52
the ratio between N2 and H2 is 1 : 3
moles H2 required = 1.52 x 3 =4.56
actual moles H2 = 10.1 g / 2.016 g/mol= 5.00 so H2 is in excess and N2 is the limiting reactant
moles NH3 = 1.52 x 2 = 3.04
mass NH3 = 3.04 x 17.0337 g/mol=51.8 g
moles H2 in excess = 5.00 - 4.56 =0.44
mass H2 in excess = 0.44 mol x 2.016 g/mol=0.887 g
Y= Slope(x) + y-int.
Y= mx +b
Y= -3x +2
The scientific notation of 3,200,000 is 3.2 * 10^6.
The number must be between 1 and 10, and we move the decimal 6 places to the left to get between 1 and 10.
Answer:
x = 10
Step-by-step explanation:
Solve for x:
-8 (8 - x) = (4 (x + 10))/5
Multiply both sides by 5:
-8×5 (8 - x) = (5×4 (x + 10))/5
(5×4 (x + 10))/5 = 5/5×4 (x + 10) = 4 (x + 10):
-8×5 (8 - x) = 4 (x + 10)
5 (-8) = -40:
-40 (8 - x) = 4 (x + 10)
Expand out terms of the left hand side:
40 x - 320 = 4 (x + 10)
Expand out terms of the right hand side:
40 x - 320 = 4 x + 40
Subtract 4 x from both sides:
(40 x - 4 x) - 320 = (4 x - 4 x) + 40
40 x - 4 x = 36 x:
36 x - 320 = (4 x - 4 x) + 40
4 x - 4 x = 0:
36 x - 320 = 40
Add 320 to both sides:
36 x + (320 - 320) = 320 + 40
320 - 320 = 0:
36 x = 40 + 320
40 + 320 = 360:
36 x = 360
Divide both sides of 36 x = 360 by 36:
(36 x)/36 = 360/36
36/36 = 1:
x = 360/36
The gcd of 360 and 36 is 36, so 360/36 = (36×10)/(36×1) = 36/36×10 = 10:
Answer: x = 10
