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3 years ago

Can y’all please explain this to me, I know the answer but I don’t know how to get it thanks

Mathematics

1 answer:

EleoNora [17]3 years ago

8 0

Answer:

250 jars

6 hours

Step-by-step explanation:

We know they make 50 jars in an hour, so 50 times 5 is 250 jars in 5 hours. Since 300 is 50 more than 250, and we know 50 times 6 is 300, we can say that we would need 6 hours to make 300 jars.

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Combine the like terms in the expression. Drag the item from the item bank to its corresponding match. Move to Top 11x4 − 13x314

Olenka [21]

They want you to combine the variables. So

−12x4 + 7x3 + 6x4 − 2x3 =

5x3 − 6x4

So you combine the coefficients, not the variable number, for instance -12+6=-6, and then you simply put the variable in the same place it was. You don't do anything else with it except what I just showed you

hope it helps

5 0

3 years ago

For each vector field f⃗ (x,y,z), compute the curl of f⃗ and, if possible, find a function f(x,y,z) so that f⃗ =∇f. if no such f

butalik [34]

$\vec f(x,y,z)=(2yze^{2xyz}+4z^2\cos(xz^2))\,\vec\imath+2xze^{2xyz}\,\vec\jmath+(2xye^{2xyz}+8xz\cos(xz^2))\,\vec k$

Let

$\vec f=f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k$

The curl is

$\nabla\cdot\vec f=(\partial_x\,\vec\imath+\partial_y\,\vec\jmath+\partial_z\,\vec k)\times(f_1\,\vec\imath+f_2\,\vec\jmath+f_3\,\vec k)$

where $\partial_\xi$ denotes the partial derivative operator with respect to $\xi$ . Recall that

$\vec\imath\times\vec\jmath=\vec k$

$\vec\jmath\times\vec k=\vec i$

$\vec k\times\vec\imath=\vec\jmath$

and that for any two vectors $\vec a$ and $\vec b$ , $\vec a\times\vec b=-\vec b\times\vec a$ , and $\vec a\times\vec a=\vec0$ .

The cross product reduces to

$\nabla\times\vec f=(\partial_yf_3-\partial_zf_2)\,\vec\imath+(\partial_xf_3-\partial_zf_1)\,\vec\jmath+(\partial_xf_2-\partial_yf_1)\,\vec k$

When you compute the partial derivatives, you'll find that all the components reduce to 0 and

$\nabla\times\vec f=\vec0$

which means $\vec f$ is indeed conservative and we can find $f$ .

Integrate both sides of

$\dfrac{\partial f}{\partial y}=2xze^{2xyz}$

with respect to $y$ and

$\implies f(x,y,z)=e^{2xyz}+g(x,z)$

Differentiate both sides with respect to $x$ and

$\dfrac{\partial f}{\partial x}=\dfrac{\partial(e^{2xyz})}{\partial x}+\dfrac{\partial g}{\partial x}$

$2yze^{2xyz}+4z^2\cos(xz^2)=2yze^{2xyz}+\dfrac{\partial g}{\partial x}$

$4z^2\cos(xz^2)=\dfrac{\partial g}{\partial x}$

$\implies g(x,z)=4\sin(xz^2)+h(z)$

Now

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+h(z)$

and differentiating with respect to $z$ gives

$\dfrac{\partial f}{\partial z}=\dfrac{\partial(e^{2xyz}+4\sin(xz^2))}{\partial z}+\dfrac{\mathrm dh}{\mathrm dz}$

$2xye^{2xyz}+8xz\cos(xz^2)=2xye^{2xyz}+8xz\cos(xz^2)+\dfrac{\mathrm dh}{\mathrm dz}$

$\dfrac{\mathrm dh}{\mathrm dz}=0$

$\implies h(z)=C$

for some constant $C$ . So

$f(x,y,z)=e^{2xyz}+4\sin(xz^2)+C$

3 0

4 years ago

What is the least common denominator for the fractions 3/16 and 11/24?

mylen [45]

Here we need to calculate common denominator so, LCM of 16 & 24

It would be 48

So, final answer is 48

Hope it helped.

3 0

3 years ago

on Tuesday afternoon at Camp Bruce Did archery and sailling before dinner he spent 55 minutes at archery and 1 hour and 35 minut

Leviafan [203]

Answer:

12:30

Step-by-step explanation:

3 0

3 years ago

Triangle abc is isosceles. what is the length of the line segment connecting the midpoints of the two sides of equal length?

Tpy6a [65]

The required relength is half of the length of AC
AC = sqrt(8 - (-2))^2 = 8 + 2 = 10

Therefore, the required length is 5.

5 0

3 years ago

Read 2 more answers