Answer: The proof is mentioned below.
Step-by-step explanation:
Here, Δ ABC is isosceles triangle.
Therefore, AB = BC
Prove: Δ ABO ≅ Δ ACO
In Δ ABO and Δ ACO,
∠ BAO ≅ ∠ CAO ( AO bisects ∠ BAC )
∠ AOB ≅ ∠ AOC ( AO is perpendicular to BC )
BO ≅ OC ( O is the mid point of BC)
Thus, By ASA postulate of congruence,
Δ ABO ≅ Δ ACO
Therefore, By CPCTC,
∠B ≅ ∠ C
Where ∠ B and ∠ C are the base angles of Δ ABC.
Answer:
128
Step-by-step explanation:
If you have any questions about the way I solved it, don't hesitate to ask!!!
Answer:
Step-by-step explanation:
<u>Solve the inequality:</u>
- - a + 1/3 > 1/4
- a < 1/3 - 1/4
- a < 4/12 - 3/12
- a < 1/12
Correct choice is B
Answer:
∠HDC ≅ ∠HDE, AB ≅ BC, HC ≅ HE
Step-by-step explanation:
yup
Answer:
I = (2,000) (0.08) (6)
I = (160) (6)
Steve pays $960 in interest
Step-by-step explanation:
I completed the quiz :)
