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3 years ago

Please answer !!!!!!!!!!!!!!!!!!! Will mark brainliest !!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

8 0

Since it is a right angle you would subtract 57 from 90 because both angles added together are 90°. 90-57= 33°

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The table shows the distance in feet, y, that a rocket traveled in x seconds.

Murrr4er [49]

Answer:

The correct option is D. y = 25 $x^{2}$ .

Step-by-step explanation:

i) From the table and our own observation and a trial and error approach we

can clearly see that the equation that matches y in feet ( the distance

traveled by the rocket) and x in seconds ( the time elapsed) is given by the

equation y = 25 $x^{2}$

Therefore the correct option is D. y = 25 $x^{2}$ .

7 0

3 years ago

Read 2 more answers

Solve: 9x - 2(4x + 5) = 2x - (4 - x) - 12 A 16 B 9 C 3 D 13

Margarita [4]

Step-by-step explanation:

4x+2x+x+9x=16x

16x=2+5+4=11

x=11

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3 years ago

I have to determine whether the sides of the triangle form a pythagorean triple.

Crazy boy [7]

Answer:

Step-by-step explanation:

How do you know if side lengths form a Pythagorean triple?

Pythagorean triples may also help us to find the missing side of a right triangle faster. If two sides of a right triangle form part of a triple then we can know the value of the third side without having to calculate using the Pythagorean theorem. From the ratio, we know that it is a Pythagorean triple.

3 0

3 years ago

I need help!<br><br> Please help!

bearhunter [10]

I think it's b

Hope I could help

6 0

3 years ago

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Construct the confidence interval for the population mean mu. c = 0.90, x = 16.9, s = 9.0, and n = 45. A 90% confidence inte

Georgia [21]

Answer:

The 90% confidence interval for population mean is $14.7 < \mu < 19.1$

Step-by-step explanation:

From the question we are told that

The sample mean is $\= x = 16.9$

The confidence level is $C = 0.90$

The sample size is $n = 45$

The standard deviation

Now given that the confidence level is 0.90 the level of significance is mathematically evaluated as

$\alpha = 1-0.90$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{\alpha }{2}$ from the standardized normal distribution table. The values is $Z_{\frac{\alpha }{2} } = 1.645$

The reason we are obtaining critical values for $\frac{\alpha }{2}$ instead of that of $\alpha$ is because $\alpha$ represents the area under the normal curve where the confidence level 1 - $\alpha$ (90%) did not cover which include both the left and right tail while $\frac{\alpha }{2}$ is just considering the area of one tail which is what we required calculate the margin of error