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2 years ago

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There are 38 pockets on an american roulette wheel: 18 red, 18 black, and 2 green. if you were to randomly spin an american roul

ette wheel, what is the probability that it would land on a green pocket

1 answer:

Pavel [41]2 years ago

8 0

You have about 5.23% chance to land in a green pocket. You can find this by dividing 2/38 or the questioned amount by the total amount of options.

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2 years ago

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Krutika and Gavin have played 41 tennis matches.

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Answer:

P(Kritika)= 27/41

P(Gavin)=1-(27/41)

= (41-27)/41

=14/41

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2 years ago

PLS HELP What is the quotient?

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Answer:

Step-by-step explanation:

$2\frac{1}{5}dividedby\frac{-1}{10}=2\frac{1}{5}*\frac{-10}{1}\\\\=\frac{11}{5}*\frac{-10}{1}\\\\=11*-2=-22\\$

Keep the first fraction, change division to multiplication and find the reciprocal(multiplicative inverse) of the second fraction

$\frac{11}{50}dividedby\frac{11}{50}=\frac{11}{50}*\frac{50}{11}\\\\ =1$

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2 years ago

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When people make estimates, they are influenced by anchors to their estimates. A study was conducted in which students were aske

12345 [234]

Answer:

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0$

where μ1: mean calorie estimation for the cheesecake group and μ2: mean calorie estimation for the organic salad group.

There is enough evidence to support the claim that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first (P-value=0.0000002).

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>"Suppose that the study was based on a sample of 20 people who thought about the cheesecake first and 20 people who thought about the organic fruit salad first, and the standard deviation of the number of calories in the cheeseburger was 128 for the people who thought about the cheesecake first and 140 for the people who thought about the organic fruit salad first.</em>

<em>At the 0.01 level of significance, is there evidence that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first?"</em>

<em />

This is a hypothesis test for the difference between populations means.

The claim is that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2> 0$

The significance level is 0.01.

The sample 1 (cheese cake), of size n1=20 has a mean of 780 and a standard deviation of 128.

The sample 2 (organic salad), of size n2=20 has a mean of 1041 and a standard deviation of 140.

The difference between sample means is Md=-261.

$M_d=M_1-M_2=780-1041=-261$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{128^2}{20}+\dfrac{140^2}{20}}\\\\\\s_{M_d}=\sqrt{819.2+980}=\sqrt{1799.2}=42.417$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-261-0}{42.417}=\dfrac{-261}{42.417}=-6.153$

The degrees of freedom for this test are:

$df=n_1+n_2-1=20+20-2=38$

This test is a left-tailed test, with 38 degrees of freedom and t=-6.153, so the P-value for this test is calculated as (using a t-table):

$P-value=P(t$

As the P-value (0.0000002) is smaller than the significance level (0.01), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the mean estimated number of calories in the cheeseburger is lower for the people who thought about the cheesecake first than for the people who thought about the organic fruit salad first.

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2 years ago

Solve for g: C = 1/2gk

sweet-ann [11.9K]

Answer:

G = $\frac{C(2)}{k}$

Step-by-step explanation:

C = 1/2gk

First you want to multiple both sides by 2 to get rid of that fraction and you get

C (2) = gk then you divide both sides by k to isolate the g and your left with

G= $\frac{C(2)}{k}$

Hope this helps

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2 years ago