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dimaraw [331]
3 years ago
7

PLZ HELP :(

Mathematics
2 answers:
goldenfox [79]3 years ago
5 0
Answer: The football field would be 91.46 meters.
lisabon 2012 [21]3 years ago
3 0

Answer: 91.46m

Step-by-step explanation: The length of 100 yard football field in meters. From the dimension given, 1 yard = 3 feet Therefore, 100 yard = x feet 1 yard = 3 feet 100 yard = x feet X = (100 × 3) / 1 X = 300 feet. But, 1 meter = 3.28feet X meter = 300 feet X = (300 × 1)  3.28X  = 91.46m Therefore, 100 yard football field is equal to 91.46m

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6x/5 - x = x/15 - 10/3
Vadim26 [7]

Answer:

x=-25

6x/5 - x = x/15 - 10/3

x/5 = x/15 - 10/3

3x = x - 50

3x - x = -50

2x = -50

x = -50/2

X=-25

4 0
2 years ago
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Help me find area please asap​
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3 years ago
Someone ask me to solve this.
Semenov [28]
X=2h, y=3k

Substitute these values into equations.

y+2x = 4 ------> 3k+2*2h=4 ----->  3k +4h =4

2/y - 3/2x = 1-----> 2/3k -3/(2*2h) = 1 ------> 2/3k - 3/4h =1

We have a system of equations now.

 3k +4h =4          ------> 3k = 4-4h ( Substitute 3k in the 2nd equation.)
2/3k - 3/4h =1

2/(4-4h) -3/4h = 1
2/(2(2-2h)) - 3/4h = 1
1/(2-2h) -3/4h - 1=0

4h/4h(2-2h) -3(2-2h)/4h(2-2h) - 4h(2-2h)/4h(2-2h) =0

(4h- 3(2-2h) - 4h(2-2h))/4h(2-2h) = 0
Numerator should be = 0
4h- 3(2-2h) - 4h(2-2h)=0

Denominator cannot be = 0
4h(2-2h)≠0

Solve equation for numerator=0
4h- 3(2-2h) - 4h(2-2h)=0
4h - 6+6h-8h+8h² =0
8h² +2h -6=0
4h² + h-3 =0
(4h-3)(h+1)=0
4h-3=0, h+1=0
h=3/4  or h=-1

Check which
4h(2-2h)≠0
1) h= 3/4  , 4*3/4(2-2*3/4)=3*(2-6)= -12 ≠0, so we can use h= 3/4
2)h=-1, 4(-1)(2-2*(-1)) =-4*4=-16 ≠0, so we can use h= -1, also.

h=3/4, then  3k = 4-4*3/4 =4 - 3=1 , 3k =1, k=1/3
h=-1, then  3k = 4-4*(-1) =8 , 3k=8, k=8/3 

So,
if h=3/4, then  k=1/3,
and if h=-1, then  k=8/3 .




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