Assuming that the inequality you were going for was a ≤, set both polynomials less than or equal to 0.
x - 3 ≤ 0
x + 5 ≤ 0
For the first equation add 3 to both sides of the inequality. For the second, subtract 5 from both sides.
x ≤ 3
x ≤ - 5
These would be your solutions I guess, however, if you want to expand upon that, your actual answer is (- ∞, - 5] because if you were to plot these two inequalities on a number line, that is where the overlap would occur.
What's the question you're asking?
Answer: I don't think any of those choices are correct.
Step-by-step explanation:
2-6*-5t+6
6*-5t+4
<h3>-30t+4</h3>
Answer:
-16 > n or n < -16
Step-by-step explanation:
First, we can write the inequality and distribute.
-6n-12 > 3(-n+12)
-6n-12 > -3n+36
Get rid of a variable first (it makes solving a lot easier). We can add 6n to both sides.
-6n-12 > -3n+36
<u>+6n +6n</u>
-12 > 3n+36
Now, we can subtract 36 on both sides.
-12 > 3n+36
<u>-36 -36</u>
-48 > 3n
Divide by 3 on both sides.
-48 > 3n
<u>/3 /3</u>
-16 > n or (if it's easier) n < -16
Hope this helps!! Have a wonderful day C:
