Anyone know how to do this??

Whats another way to write 300 70 5/10 8/100?

Triss [41]

I do not think we need to rewrite the first two numbers in the given above because they are already the simplest forms of themselves being whole numbers. However, the third number may be rewritten as 1/2 by dividing both numerator and denominator by 5 and the last one as 2/25 by dividing both numerator and denominator by 4.

3 0

4 years ago

Read 2 more answers

A square has side length (x+5) units. What is it’s area

daser333 [38]

The area of square is $x^{2}+10 x+25$ square units

<h3><u>Solution:</u></h3>

Given that square has side length (x+5) units

To find: area of square

<em><u>The area of square is given as:</u></em>

$\text {Area of square }=\mathrm{a}^{2}$

Where "a" is the length of side

From question, length of each side "a" = x + 5 units

Substituting the value in above formula,

$\text {Area of square }=(x+5)^{2}$

${\text {Expanding }(x+5)^{2} \text { using the algebraic identity: }} \\\\ {(a+b)^{2}=a^{2}+2 a b+b^{2}}\end{array}$

$\begin{array}{l}{\text {Area of square }=x^{2}+2(x)(5)+5^{2}} \\\\ {\text {Area of square }=x^{2}+10 x+25}\end{array}$

Thus the area of square is $x^{2}+10 x+25$ square units

7 0

3 years ago

A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation i

velikii [3]

Answer: One tail test.

Step-by-step explanation:

Given : A sample of 36 observations is selected from a normal population. The sample mean is 12, and the population standard deviation is 3.

Also, The set of hypothesis to conduct a test :-

$H_0:\mu\leq10\\\\H_1:\mu>10$

The kind of test need to perform is dependent upon the alternative hypothesis.

Since, the alternative hypothesis is one tailed (right-tailed), so the test is one tail test.

5 0

4 years ago

The lines y1 = 2x - 6, y2 = -3x + 4, y3 = -1/2x + 4 are the sides of a right triangle. Find the perimeter and area of the triang

sergiy2304 [10]

The area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

<h3>Perimeter and area of the triangle giving the equation of a line</h3>

First we will plot the giving lines, determine the point of intersection and then use the Pythagoras theorem to determine the dimension of the right triangle.

From the given equation of the lines, the points of intersection of the line are (x₁, y₁) = (- 0.4, 5.2), (x₂, y₂) = (-0.8, 4.4) and (x₃, y₃) = (0, 4)

For the base

b² = c² -a²

b = √(-0.8)² + (4 - 4.4)²

b = 2√5 / 5

For the height

h = √((- 0.4) - (- 0.8))² + (5.2 - 4.4)²

height = 2√5 / 5

For the hypotenuse

r = √2 · b

r = 2√10 / 5

<h3>Determine the Perimeter and area</h3>

Perimeter = s1+s2+s3

Perimeter = 2√5 / 5 + 2√5 / 5 + 2√10 / 5

Perimeter = (2√10 + 4√5) / 5 units

area = 1/2* base * height

A = 0.5 · (2√5 / 5) · (2√5 / 5)

A = 2/5 square units

Hence the area and perimeter of the triangle is 2/5 square units and (2√10 + 4√5) / 5 units

Learn more on area and perimeter of triangles here: brainly.com/question/21511715

#SPJ1

8 0

2 years ago

A real estate agent sold Amar's home so he could relocate for a job. The company hiring Amar paid the real estate agent $14,000,

sasho [114]

The house is 91000 dollars. 14000 x 6.5
F U jackmac

3 0

3 years ago