The sum of the interior angles of<span> a </span>triangle<span> are equal to 180</span>o<span>. To </span>find the third angle of a triangle<span> when the other two </span>angles<span> are known subtract the number of degrees in the other two </span>angles<span> from 180</span><span>o</span>
(32-n)470
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Answer:
BC < CE < BE < ED < BD
Step-by-step explanation:
In the triangle BCE,
m∠BEC + m∠BCE + m∠CBE = 180°
m∠BEC + 81° + 54° = 180°
m∠BEC = 180 - 135
m∠BEC = 45°
Order of the angles from least to greatest,
m∠BEC < m∠CBE > mBCE
Sides opposite to these sides will be in the same ratio,
BC < CE < BE ----------(1)
Now in ΔBED,
m∠BEC + m∠BED = 180°
m∠BED = 180 - 45
= 135°
Now, m∠BDE + m∠BED + DBE = 180°
11° + 135°+ m∠DBE = 180°
m∠DBE = 180 - 146
= 34°
Order of the angles from least to greatest will be,
∠BDE < ∠DBE < ∠BED
Sides opposite to these angles will be in the same order.
BE < ED < BD ----------(2)
From relation (1) and (2),
BC < CE < BE < ED < BD
Answer:
Step-by-step explanation:
Answer:
y=-1/4x
Step-by-step explanation:
METHOD 1: The basic slope-intercept equation is <em>y=ax+b</em>. To achieve the slope with two points, this is the equation:
All you have to do is insert points (-4, 1) and (4, -1) into their corresponding locations.
With this equation, you will be able to find the slope. Then you can simply graph it to connect the two dots.
METHOD 2: Simply connect the two dots with a straight line (use a ruler or something with a straight edge.) Then count how many spaces up/down and left/right. If the line goes from top to bottom from left to right, it is a negative slope (hence, the -1/4.)
