1. Find the missing measure.<br> 65°

Use the drop-down menu to create true statements,

taurus [48]

Answer:

A) Vertical test

B) y=x

C) x

D) domain

5 0

3 years ago

Assume that price is an integer variable whose value is the price (in US currency) in cents of an item. Assuming the item is pai

cestrela7 [59]

Answer:

$Change = (Paid*100) - Price$

Step-by-step explanation:

First of all we need to know the relation between 1 dollar and 1 cent in order to express everything in the units required in the question.

We know that $1 dollar = 100 cents$ , so the amount paid for the item with single dollars has to be multiplied by 100 to express its value in cents.

$Paid_{cents}=Paid_{dollars}*100$

Now that we have everything in cents, we can make the subtraction:

$Change_{cents} = Paid_{cents} -Price_{cents}$

Replacing the value in cents we get:

$Change = (Paid*100) - Price$

4 0

3 years ago

The derivative of y with respect to x, when y = 3e^5x - 2 is:

Ede4ka [16]

Answer: 15e^5x

Step - by - step

y=3e^5x - 2

By the sum rule, the derivative of 3e^5x - 2 with respect to x is d/dx [ 3e^5x ] + d/dx [-2].

d/dx [ 3e^5x ] + d/dx [ -2 ]

Evalute d/dx [ 3e^5x ]

Since 3 is constant with respect to x , the derivative of 3e^5x with respect to x is
3 d/dx [ e^5x ].

3 d/dx [ e^5x ] + d/dx [ -2 ]

Differentiate using the chain rule, which states that d/dx [ f(g(x))] is f' (g(x)) g' (x) where f(x) = e^x and g(x) = 5x.

To apply the Chain Rule, set u as 5x.
3 ( d/du [ e^u] d/dx [5x] ) + d/dx [ -2]

Differentiate using the Exponential rule which states that d/du [ a^u ] is a^u ln(a) where a=e.

3( e^u d/dx[5x] ) + d/dx [ -2 ]
Replace
3(e^5x d/dx [5x] ) + d/dx [ -2 ]
3(e^5x( 5 d/dx [x] )) + d/dx [ -2 ]

Diffentiate using the Power Rule which states that d/dx [x^n] is nx^n-1 where n=1.
3(e^5x(5*1)) + d/dx [-2]
3 ( e^5x * 5 ) + d/dx [-2]

Multiply 5 by 3
15e^5x + d/dx [-2]

Since -2 is constant with respect to x, the derivative of -2 with respect to x is 0.
15e^5x + 0
15e^5x

5 0

9 months ago

Solve 2x^2=11x+6 by factoring

Ede4ka [16]

Answer:

(x-6) (2x+1)

Step-by-step explanation:

1) move everything over to the left side, so subtract 11x and 6.

2x^2 -11x - 6 = 0

2)multiply 2(a term) with -6 (c term)

x^2 -11x -12

3) factor and find what multiples to -12 and adds up to -11. in this case its -12 and positive 1

(x-12) (x+1)

4) divide -12 and 1 by the original a term (2)

(x-6) (x+1/2)

5) move the denominator of 2 over to the x.

(x-6) (2x+1)

5 0

3 years ago

To see how costly it would be for other people to compete a similar cycling tour, you decide to work out two averages and compar

Damm [24]

Group A

Money spent by Person 1 = £500

Money spent by Person 2 = £600

Money spent by Person 3 = £900

Money spent by Person 4 = £450

Sum of money spent by group A = £2,450

Average money spent by group A = $\frac{2,450}{4}$

⇒ Average money spent by group A = £612.5

Group B

Money spent by Person 1 = £700

Money spent by Person 2 = £500

Money spent by Person 3 = £680

Money spent by Person 4 = £500

Sum of money spent by group B = £2,380

Average money spent by group B = $\frac{2,380}{4}$

⇒ Average money spent by group B = £595

Hence, Group B had lower average spend.

4 0

2 years ago

1. Find the missing measure. 65°