All categories

3 years ago

Helppppp mee eeeee eee

Computers and Technology

2 answers:

almond37 [142]3 years ago

8 0

Answer:

Explanation: bc it is

ExtremeBDS [4]3 years ago

7 0

Answer:

Explanation:

trust me OK, I know how to drive

You might be interested in

Design a class called NumDays. The class’s purpose is to store a value that represents a number of work hours and convert it to

stepladder [879]

Answer:

See explaination

Explanation:

#include <iostream>

using namespace std;

class NumDays{

int hours;

float day;

public:

NumDays()

{

hours=0;

day=0.0;

};

NumDays(int h)

{

hours=h;

day=float(h/8.0);

};

int getHour()

{

return hours;

}

float getDay()

{

return day;

}

NumDays operator +(NumDays obj)

{

int h=getHour()+obj.getHour();

NumDays temp(h);

return temp;

}

NumDays operator -(NumDays obj)

{

int h=getHour()-obj.getHour();

NumDays temp(h);

return temp;

}

const NumDays& operator++() //prefix

{

++hours;

day=float(hours/8.0);

return *this;

}

const NumDays& operator--() //prefix

{

--hours;

day=float(hours/8.0);

return *this;

}

const NumDays operator++(int) //postfix

{

NumDays temp(*this);

++hours;

day=float(hours/8.0);

return temp;

}

const NumDays operator--(int) //postfix

{

NumDays temp(*this);

--hours;

day=float(hours/8.0);

return temp;

}

};

int main()

{

NumDays obj(2),obj2(10),obj3,obj4;

obj3=obj2-obj;

cout<<"'obj3=obj2-obj'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj3=obj+obj2;

cout<<"'obj3=obj+obj2'=> Day:"<<obj3.getDay()<<"##Hour:"<<obj3.getHour()<<"\n";

obj4=obj3++;

cout<<"'obj4=obj3++' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=++obj3;

cout<<"'obj4=++obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=obj3--;

cout<<"'obj4=obj3--' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

obj4=--obj3;

cout<<"'obj4=--obj3' => Day:"<<obj4.getDay()<<"##Hour:"<<obj4.getHour()<<"\n";

};

3 0

3 years ago

Because all web browsers don't interpret html and css the same way, a major web development issue is

Triss [41]

Cross browser. Hope I am right.

8 0

4 years ago

A certain manager makes the following statement "Our internet company is in business for the money, making profits, and making t

julia-pushkina [17]

Answer:

d. Stockholder theory

Explanation:

The theory of maximising profits

8 0

4 years ago

Your essay is due tomorrow and you don't have time to write it. You decide to buy an essay online. You've paid for it, so it can

viva [34]

Answer:

false

even though you have paid for it , you still didn't write it by yourself, there for it will still be seen as plagiarism.......hope this helps

4 0

4 years ago

A 1 MB digital file needs to transmit a channel with bandwidth of 10 MHz and the SNR is 10 dB. What is the minimum amount of tim

hodyreva [135]

Answer:

A 1 MB digital file needs 0.23 seconds to transfer over a channel with bandwidth 10 MHz and SNR 10 dB.

Explanation:

We can calculate the channel capacity using Shannon's Capacity formula:

C = B + log₂ (1 + SNR)

Where C = Channel Capacity

B = Bandwidth of the Channel

SNR = Signal to Noise Ratio

We are given SNR in dB so we need to convert it into a ratio.

$SNR_{dB}$ = 10log₁₀ (SNR)

10 = 10log₁₀ (SNR)

1 = log₁₀ (SNR)

SNR = 10¹

SNR = 10

So, using Shannon Channel Capacity formula:

C = 10 x 10⁶ log₂ (1 + 10)

C = 34.5 MHz

Total amount of time required to transmit a 1MB file:

1MB = 1 x 8 Mbytes = 8Mb

C = 34.5 MHz = 34.5 Mb/s

Time required = 8Mb/34.5Mb/s = 0.23 seconds

A 1 MB digital file needs 0.23 seconds to transfer over a channel with bandwidth 10 MHz and SNR 10 dB.

8 0

3 years ago