Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros −3 and 5
+i.
1 answer:
Answer:
<em>f(x) = x² (2+i)x-15-3i</em>
Step-by-step explanation:
Since the zeros of the equation are -3 and 5+i, hence the factors of the polynomial in x is (x+3) and (x-(5+i))
Multiplying both factors
f(x) = (x+3)(x-(5+i))
f(x) = (x²-(5+i)x+3x -3(5+i))
f(x) = x² - (5+i- 3)x -15-3i
f(x) = x² (2+i)x-15-3i
<em>hence the required polynomial function in x is f(x) = x² (2+i)x-15-3i</em>
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Answer:
7/3
Step-by-step explanation:
in decimal 2.3
in fraction 2 1/3
M= 20 because the rate of change is -3.
30 with the remainder of 714
Your answer would be x-4=17.
4 less than (#) is 17.
That number would be 21.
21-4=17
Hope that helps
I think its A because if you think about it 6 and 12 its a easy possiblility so it is A i think
