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denpristay [2]
3 years ago
14

​John's House of Pancakes uses a weighted moving average method to forecast pancake sales. It assigns a weight of 5 to the previ

ous​ month's demand, 3 to demand two months​ ago, and 1 to demand three months ago. If sales amounted to​ 3,000 pancakes in​ May, 2,200 pancakes in​ June, and​ 1,000 pancakes in​ July, what should be the forecast for​ August? A. ​3,767 B. ​1,622 C. ​2,067 D. ​2,400 E. ​2,511
Mathematics
1 answer:
NikAS [45]3 years ago
7 0

Answer:

B. ​1,622

Step-by-step explanation:

The weighed average is each value multiplied by it's weight divided by the sum of the weights.

In this problem we have that:

Weight of 5 to the previous month demand. The number of pancakes in July was 1000.

Weight of 3 to the demand of two months ago. The number of pancakes in June was 2200.

Weight of 1 to the demand of three months ago. The number of pancakes in May was 3000.

So, the forecast for August is:

M = \frac{5*1000 + 3*2200 + 1*3000}{9} = 1622.2

The forecast for August is a demand of 1622 pancakes. Letter B.

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kirza4 [7]

Answer:15+2.50(10x3)=x

Step-by-step explanation:

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2 years ago
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P = A + B + C Find P if A = 23 B = 17 C = 29 P=​
madam [21]

Answer:

P = 69!

Step-by-step explanation:

23+17+29 = 69 :)

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3 years ago
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If a positive integer is equal to the following product: 25b3c425b3c4, where b and c are distinct prime numbers greater than 2,
Vlad [161]

Answer: 64 distinct even factors

Step-by-step explanation:

let the 2 distinct numbers be b and c and the integer is expected to be 25b3c425b3c4

since b, c > 2 and prime numbers,

potential options include 3, 5, and 7

hence the likelihoods are (b = 3, c = 5), (b = 5, c = 3), (b = 3, c = 7), (b = 7, c = 3), (b = 5, c = 7), (b = 7, c = 5)

Possibility 1 (b = 3, c = 5)

integer is now 253354253354

the distinct even factors = 2, 202, 262, 1934, 19802, 26462, 195334, 253354, 2000002, 2594062, 19148534, 25588754, 262000262, 1934001934, 2508457954, 253354253354

number of distinct even factors = 16

Possibility 2 (b = 5, c = 3)

integer is now 255334255334

the distinct even factors = 2, 86, 202, 5938, 8686, 19802, 253354, 599738, 851486, 2000002, 25788734, 58792138, 25588754, 86000086, 2528061934, 1934001934, 5938005938, 253354253354

number of distinct even factors = 18

Possibility 3 (b = 3, c = 7)

integer is now 253374253374

the distinct even factors = 2, 6, 22, 66, 202, 242, 606, 698, 726, 2094, 2222, 6666, 7678, 19802, 23034, 24442, 59406, 70498, 73326, 84458, 211494, 217822, 253374, 653466, 775478, 2000002, 2326434, 2396042, 6000006, 6910898, 7188126, 8530258, 20732694, 22000022, 25590774, 66000066, 76019878, 228059634, 242000242, 698000698, 726000726, 836218658, 2094002094, 2508655974, 7678007678, 23034023034, 84458084458,253354253354

number of distinct even factors = 48

Possibility 4 (b = 7, c = 3)

integer is now 257334257334

the distinct even factors = 2, 6, 14, 22, 42, 66, 154, 202, 462, 606, 1114, 1414, 2222, 3342, 4242, 6666, 7798, 12254, 15554, 19802, 23394, 36762, 46662, 59406, 85778, 112514, 138614, 217822, 257334, 337542, 415842, 653466, 787598, 1237654, 1524754, 2000002, 2362794, 3712962, 4574262, 6000006, 8663578, 11029714, 14000014, 22000022, 25990734, 33089142, 42000042, 66000066, 77207998, 121326854, 154000154, 231623994, 363980562, 462000462, 849287978, 1114001114, 2547863934, 3342003342, 7798007798, 12254012254, 23394023394, 36762036762, 85778085778, 257334257334

number of distinct even factors = 64

Possibility 5 (b = 5, c = 7)

integer is now 255374255374

the distinct even factors = 2, 14, 34, 58, 74, 202, 238, 406, 518, 986, 1258, 1414, 2146, 3434, 5858, 6902, 7474, 8806, 15022, 19802, 24038, 36482, 41006, 52318, 99586, 127058, 138614, 216746, 255374, 336634, 574258, 697102, 732674, 889406, 1517222, 2000002, 2356438, 3684682, 4019806, 5128718, 9762386, 12455458, 14000014, 21247546, 25792774, 34000034, 58000058, 68336702, 74000074, 87188206, 148732822, 238000238, 361208282, 406000406, 518000518, 986000986, 1258001258, 2146002146, 2528457974, 6902006902, 8806008806, 15022015022, 36482036482, 255374255374

number of distinct even factors = 64

Possibility 6 (b = 7, c = 5)

integer is now 257354257354

the distinct even factors = 2, 202, 19802, 257354, 2000002, 25992754, 2548061954, 257354257354

number of distinct even factors = 8

From the six possibilities, the highest number of likely distinct even factors is 64

7 0
3 years ago
Ben is going to make 1/4 pound burgers for a barbecue next weekend. He is planning on making 19 burgers. How much hamburger meat
Monica [59]

Answer:

4.75 pounds of hamburger meat

Step-by-step explanation:

In order to calculate the total amount of hamburger meat that Ben would need we would need to multiply the total number of burgers that he wants to make (19) by the amount of meat each burger will use (1/4 pound or 0.25 pound). Therefore, we would do the following...

19 * 0.25 = 4.75 pounds

Finally, we can see that Ben would need a total of 4.75 pounds of hamburger meat to make 19 equal sized 1/4 pound burgers.

4 0
3 years ago
Which function describes the sequence 4, 8, 16, 32 …
Viktor [21]

Answer:

I think that the answer is 2 power n , so A is the correct choice .

3 0
3 years ago
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