Answer:
So the ratio is 5:4:3
As there are 60 clown fish, divide 60 by 5. =12
12 x 4 = 48 (amount of angel fish)
12 x 3 = 36 (amount of goldfish)
Answer:
Step-by-step explanation:
Given
Required
Solve
Using sine rule, we have:
This gives:
So, we have:
In radical forms, we have:
Take LCM
Rewrite as:
Hence:
Answer:
1) Event A = 2/3
Event B = 1/2
2) 1/2
Step-by-step explanation:
1)
Event A :
No. we need on dice = 4
Total numbers on dice = 6
Hence sample space of the event = 6
P( getting 4) = 4/6 = 2/3
Event B :
A coin has a head & a tail.
Hence sample space of the event = 2
But as we need tail only ,
P ( getting Tail ) = 1/2 [ if only tossed once ]
2)
Total numbers on a die = 6
Total no. of odd numbers on die = 3 (∵ 1 , 3 & 5 are odd )
Sample space of this event = 6
P (getting an odd number) = 3/6 = 1/2
Answer:
C (reflection across the x access)
Step-by-step explanation:
I got it right on edge
Answer is -5.
Explanation- Since t equals 0. You put 0 in place of every t.
0(2)- 2(0)- 5 =
0-0-5= -5
