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3 years ago

Help please please help ASAP * please don’t answer if you don’t know

Mathematics

1 answer:

Julli [10]3 years ago

3 0

Answer:

Your answer is x = 24 , y =8√3

Step-by-step explanation:

Sorry for late answer actually I was preparing for my exams. ❤

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The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l

sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

$A=\frac{\sqrt{3} }{4} x^2$

(c)

$A=\frac{3\sqrt{3} }{2} x^2$

(d)

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

$=\frac{\sqrt{3} }{4} b^2$

h=3x

b=x

now, we can plug values

$A=\frac{\sqrt{3} }{4} x^2$

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

$=6\times \frac{\sqrt{3} }{4} x^2$

$=\frac{3\sqrt{3} }{2} x^2$

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

$=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)$

$V=\frac{3\sqrt{3} }{2} x^3$ units^3

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Answer:

$\textbf{Option 1}\\$

Step-by-step explanation:

$\textup{Given $ Ax + By = -C$}\\\textup{Subtracting $By$ on both sides, we get,}\\$ Ax = -C -By $\\$

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erastovalidia [21]

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ArbitrLikvidat [17]

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borishaifa [10]

Answer:

4(a-2)+a=4a-2 No solution

Step-by-step explanation:

This would never be true. Try plugging in a as 1.

4(1-2)+1 isn't equal to 4(1)-2.

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