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Aleksandr-060686 [28]
3 years ago
15

Find the y-intercept of the following equation. Simplify your answer. y = 8x + 10 y-intercept=​

Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

10

Step-by-step explanation:

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Simplify (x⁴)³. <br><br><br> pls help
Alex_Xolod [135]

Answer:

x^{12}

Step-by-step explanation:

Step 1: Equation

(x^{4})^3

Step 2: Exponent Property: Power of a Power

x^4×3 = x^{12}

Answer:

x^{12}

Hope This Helps :)

5 0
3 years ago
Read 2 more answers
HELLO!!! I nEeD hElP
katovenus [111]

Answer:a

Step-by-step explanation:

I just did it

6 0
3 years ago
Suppose that $p$ and $q$ are positive numbers for which \[\log_9 p = \log_{12} q = \log_{16} (p + q).\] what is the value of $q/
SVEN [57.7K]

Given p,q>0 and \log_9p=\log_{12}q=\log_{16}(p+q)=x (say).

Then,

p=9^x\\ q=12^x\\ p+q=16^x

From the above 3 equations,

\frac{q}{p} =(\frac{12}{9} )^x\\ \frac{q}{p} =(\frac{4}{3} )^x\\ \frac{p+q}{p} =(\frac{16}{9} )^x\\ \frac{p+q}{p} =(\frac{4}{3} )^{2x}\\

From the equations, we get

\frac{p+q}{p}=(\frac{q}{p})^2\\ 1+\frac{q}{p}=(\frac{q}{p})^2\\ (\frac{q}{p})^2-\frac{q}{p}-1=0\\ \frac{q}{p}=\frac{1 \pm \sqrt{5}}{2}

Since p,q>0, the negative value is rejected.

\frac{q}{p}=\frac{1 + \sqrt{5}}{2}

3 0
3 years ago
Find the 27th term in the arithmetic sequence of 59,56,53,50
statuscvo [17]

solution:

A_{n}=59-3(n-1)\\where, n=1,2,3,.....\\A1=59\\A2=56\\A3=53\\A_{n}=a+(n-1)dA27=59+(27-1)3\\=59-78\\=-19\\A27 term is -19

5 0
3 years ago
70 POINTS SHOW WORK
lord [1]
Area of triangle = 1/2 x base x height

so old triangle we have  1/2 x b x h = 48

new triangle has base 3 times as long and height is half as long
 so we would get:

1/2 x (3B) x (1/2H) = area

rewrite as 1/2 x 3/2 x b x H = area

divide by original are os 1/2 x b x h and you end up with 3/2

so new area = 3/2 x old area

new area = 3/2 * 48 = 72 square inches
8 0
3 years ago
Read 2 more answers
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