Answer:
13 and -14 satisfy this condition
Step-by-step explanation:
Let's represent that number as x
and the square of x is x^2
So,
x + x^2 = 182
Subtract 182 from both sides
x + x^2 - 182 = 182 - 182
x + x^2 - 182 = 0
rearrange the quadratic equation
x^2 + x -182 = 0
let's use the quadratic formula
or ![\frac{-b-\sqrt{b^2-4ac} }{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b-%5Csqrt%7Bb%5E2-4ac%7D%20%7D%7B2a%7D)
a = 1, b = 1, c = -182
or ![\frac{-1-\sqrt{1^2-4*1*(-182)} }{2*1}](https://tex.z-dn.net/?f=%5Cfrac%7B-1-%5Csqrt%7B1%5E2-4%2A1%2A%28-182%29%7D%20%7D%7B2%2A1%7D)
or ![\frac{-1-\sqrt{1+728} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-1-%5Csqrt%7B1%2B728%7D%20%7D%7B2%7D)
or ![\frac{-1-\sqrt{729} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-1-%5Csqrt%7B729%7D%20%7D%7B2%7D)
or ![\frac{-1-{27} }{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-1-%7B27%7D%20%7D%7B2%7D)
or ![\frac{-28}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B-28%7D%7B2%7D)
13 or - 14
Lets check
13 + 13^2 = 13 + 169
= 182
Also,
-14 + (-14^2) = -14 + 196
= 182
i need more information to answer the question
Answer:
73
Step-by-step explanation:
to find the mean you need to add up all grades and divide if by the number of terms you added
(82 + 88 + x) ÷ 3 = 69 (since we don't know the third grade let's call it x)
170 + x = 69 × 3
x = 37
if the digits transposed the the actual grade would be 73
Answer:
19.77% of average city temperatures are higher than that of Cairo
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
![\mu = 19.7, \sigma = 2](https://tex.z-dn.net/?f=%5Cmu%20%3D%2019.7%2C%20%5Csigma%20%3D%202)
What percentage of average city temperatures are higher than that of Cairo?
This is 1 subtracted by the pvalue of Z when X = 21.4.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{21.4 - 19.7}{2}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B21.4%20-%2019.7%7D%7B2%7D)
![Z = 0.85](https://tex.z-dn.net/?f=Z%20%3D%200.85)
has a pvalue of 0.8023
1 - 0.8023 = 0.1977
19.77% of average city temperatures are higher than that of Cairo