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Amanda [17]
3 years ago
12

What do you call identical twin sisters when both are ice skating championships?

Mathematics
1 answer:
kondaur [170]3 years ago
8 0
Ice queen clones Hope this helps! :D
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In a class of 20 students, 40% are boys. 25% of the boys and 50% of the girls wear glasses. How many students wear glasses?
fredd [130]
Calcualate 40% (0.40) times 20 to get that there are 8 boys in the class. The rest must be girls, so 20 - 8 gives you 12 girls. 25% (0.25) times the 8 boys gives you that 2 of the boys wear glasses. 50% (0.5) times the 12 girls tives you that 6 girls wear glasses. Add together the 2 boys and the 6 girls that wear glasses to get that a total of 8 students wear glasses.
3 0
3 years ago
Help on algebra please?
rodikova [14]
The first option is the one!

6 0
3 years ago
Read 2 more answers
What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
LenKa [72]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

5 0
3 years ago
Nguyen played a game in which he could either lose or gain points each round. at the end of 7 rounds, he had -8 points. After on
Sergeeva-Olga [200]

Answer:

I think the answer would be +15.

Step-by-step explanation:

3 0
2 years ago
Assume Cylinder A and Cone B are the same height and the bases have the same radius. If A has a volume of 18π cm3, what is the v
disa [49]

Answer:

Option A  V_B=19\ cm^3

Step-by-step explanation:

The volume of a cone is:

V_B = \pi\frac{hr ^ 2}{3}

The volume of a cylinder is:

V_A = \pi(r ^ 2)h

Both figures have the same height h and the same radius r.

The volume of the cylinderV_A = 18\pi\ cm ^ 3

We want to find the volume of the cone.

Then, we find r and h:

V_A = 18\pi = \pi(r ^ 2)h

We simplify.

V_A = 18 = (r ^ 2)h

Then the product of (r ^ 2)h = 18.

We substitute this in the cone formula and get:

V_B =\frac{\pi}{3}(18)\\\\V_B = \frac{18}{3}\pi\\\\V_B=19\ cm^3

8 0
3 years ago
Read 2 more answers
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