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Nezavi [6.7K]
3 years ago
5

ASAP On the coordinate plane below, quadrilaterals TRAP and HELP are similar to each other.

Mathematics
2 answers:
monitta3 years ago
7 0

Answer:

1:2.

Step-by-step explanation:

HP and TP are corresponding sides and their lengths are  2 and 4.

Thats a ratio of 1 :2.

The perimeter is also one dimensional so the ratio of the perimeters is also 1:2.

ipn [44]3 years ago
5 0

Answer:

1 : 2

Step-by-step explanation:

Since the quadrilaterals are similar then the ratios of corresponding sides are equal, that is

\frac{HP}{TP} = \frac{2}{4} = \frac{1}{2}

Thus the ratio of perimeters is also 1 : 2

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Answer:

Im not 100% sure but I got 1.66667 so therefore I would say about 4:00 maybe? Didn't really understand lmk.

Step-by-step explanation: I added 46, 29, and 25 together which gave me 100 and i put that into minutes which gave me 1.66667 which rounds to 1.70 and so if 60 seconds is 1 hour than 2:00 plus 2 hours is 4. That's what I got out of it.

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A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

We dont know the true proportion, so we use \pi = 0.5, which is when we are are going to need the largest sample size.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.04}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2

n = 600.25

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2

n = 2401

The minimum sample size is 2401.

4 0
3 years ago
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