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Levart [38]
3 years ago
8

The hypotenuse of a right triangle is 5cm long the longer leg is 1cm longer than the shorter leg find the side lengths of the tr

iangle
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
5 0

Answer:

<em>Shorter leg=3</em>

<em>Longer leg=4</em>

Step-by-step explanation:

<u>Equations</u>

In a right triangle, Pythagora's Theorem is satisfied. Being a the hypotenuse, b and c the legs of the triangle, then:

a^2=b^2+c^2

Let's call

x=the shorter leg of the triangle

The longer leg is 1 cm longer than the shorter leg, thus:

x+1=the longer leg.

Since the hypotenuse is 5 cm long:

5^2=x^2+(x+1)^2

Operating:

25=x^2+x^2+2x+1

Swapping sides and simplifying:

2x^2+2x+1=25

Subtracting 25:

2x^2+2x-24=0

Dividing by 2:

x^2+x-12=0

Factoring:

(x-3)(x-4)=0

We have two possible solutions:

x=3, x=4

The longer leg is x+1.

If x=3, x+1=4

If x=4, x+1=5. This solution is not valid because one leg would be equal to the hypotenuse.

Thus, the solution is:

Shorter leg=3

Longer leg=4

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Step-by-step explanation:

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15 is a whole number so it applies to everything except for irrational numbers

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2 years ago
Country days scholarship rounds receive a gift of $135000. The money is invested in stock, bonds, and CDs. CDs pay 2.75% interes
Vsevolod [243]

Answer:

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Step-by-step explanation:

Let the variables c, b, s represent the dollar amounts invested in CDs, stocks, and bonds, respectively. Then the problem statement gives us 3 relations between these 3 variables:

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Using the third equation to write an expression for b, we can substitute into the other two equations.

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  .0275c +.045(70000 +c) +.104s = 8555 . . . . . substitute for b in 2nd eqn

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Using [eq4], we can write an expression for s that can be substituted into [eq5].

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Alternatively, you can reduce the augmented matrix for this problem to row-echelon form using any of several calculators or on-line sites. That matrix is ...

\left[\begin{array}{ccc|c}1&1&1&135000\\0.0275&0.045&0.104&8555\\-1&1&0&70000\end{array}\right]

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3 years ago
Find angle A and angle B..​
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Step-by-step explanation:

\sf{\bold{\blue{\underline{\underline{Given}}}}}

\tt{\angle{c}=110°}

and,

\tt{BC=AC}

⠀⠀⠀⠀

\sf{\bold{\red{\underline{\underline{To\:Find}}}}}

☆Find the \angle{B} ~and~\angle{A}

\sf{\bold{\purple{\underline{\underline{Solution}}}}}

Here,

BC =AC

so,

⠀⠀⠀

\angle{A}=\angle{B}

we know that,

\tt{\boxed{\pink{\angle{A}+\angle{B}+\angle{C}=180°}}}

But \angle{C}=110°(Ģìvéñ)

so..

\angle{A}+\angle{B}+110°=180°

\angle{A}+\angle{A}+110°=180°

\because{\angle{A}=\angle{B} }

2\angle{A}=180°-110°

2\angle{A}=70°

\angle{A}=\dfrac{70°}{2}

\boxed{\orange{\angle{A}=35°}}

But...

\angle{A}=\angle{B}

soo,

\boxed{\orange{\angle{B}=35°}}

\sf{\bold{\green{\underline{\underline{Answer}}}}}

⠀⠀⠀⠀

\boxed{\green{\angle{A}=35°}}

\boxed{\green{\angle{B}=35°}}

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Answer:

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4 0
2 years ago
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