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3 years ago

How many pairs of whole numbers have the Sum of 12

1 answer:

nataly862011 [7]3 years ago

8 0

Thanks for the question!

Don't forget 0 is a whole number:

0 + 12
1 + 11
2 + 10
3 + 9
4 + 8
5 + 7
6 + 6

Hope this helps!

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Solve for x x-4=-7. Please

Alecsey [184]

Answer:

-3

Step-by-step explanation:

x - 4 = - 7

Carry over the - 4 and make x the subject.

x= - 7 + 4

x= - 3

Therefore x is - 3

8 0

3 years ago

Question 3 (1 point)

lana66690 [7]

Answer: The area of the new parallelogram is multiplied by 18

Step-by-step explanation: Let the base and the height of the original parallelogram be ' x '

Base of the parallelogram = x

Height of the parallelogram = x

Area of parallelogram = l × b = lb

= x × x = x²

∴ Area of the original parallelogram = x²

∴ The base is multiplied by 3 = 3x

The height is multiplied by 6 = 6x

∴ Area of new parallelogram = 3x × 6x = 18x²

∴ The area of the new parallelogram is multiplied by = 18x²/ x²

= 18

<u><em>Please mark this as brainliest</em></u>

7 0

3 years ago

The dot plots below show the ages of students belonging to two groups of music classes:

kolbaska11 [484]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Slope????????????????

MAXImum [283]

M = Undefined (because the line is perfectly vertical)

6 0

3 years ago

Find the logarithmic function y = logbx that passes through the points

katovenus [111]

$b\in(0,\ 1)\ \cup\ (1,\ \infty)\\x > 0\\y\in\mathbb{R}\\--------------------------\\\\y=\log_bx\\\\For\ (1,\ 0)\to x=1,\ y=0.\ Substitute:\\\\\log_b1=0\to b^0=1\to b\in(0,\ 1)\ \cup\ (1,\ \infty)\\\\For\ (116,\ 2)\to x=116,\ y=2.\ Substitute:\\\\\log_b116=2\to b^2=116\to b=\sqrt{116}\\\to b=\sqrt{4\cdot29}\to b=\sqrt4\cdot\sqrt{29}\to b=2\sqrt{29}\\\\For\ (4,\ -1)\to x=4,\ y=-1.\ Substitute:\\\\\log_b4=-1\to b^{-1}=4\to b=\dfrac{1}{4}$

Different values of b.

<h3>Answer: There is no logarithmic function whose graph goes through given points.</h3><h3 />

Maybe the second point is $\left(\dfrac{1}{16},\ 2\right)$

Substitute:

$\log_b\dfrac{1}{16}=2\to b^2=\dfrac{1}{16}\to b=\sqrt{\dfrac{1}{16}}\to b=\dfrac{1}{4}$

<h3>Then we have the answer:</h3>

$\boxed{y=\log_{\frac{1}{4}}x}$

6 0

3 years ago