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3 years ago

Whenever a,x,y are positive integers, which of the following expressions is equivalent to x^ay^a

Mathematics

1 answer:

lilavasa [31]3 years ago

3 0

Answer:

${(xy)}^{a}$

Step-by-step explanation:

when the exponent is equal, we can put the x and y together in a bracket and a as the Exponent of xy.

Hope I get your question~

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A new car worth $18 comma 000 is depreciating in value by $3 comma 000 per year. after how many years will the car's value be

ehidna [41]

Its 5 years
worth = 18000
depriciation per year= 3
in 5 year car value= 18000 minus 5×3000= 3000

8 0

3 years ago

Can someone plz help me solved this problem I need help plz help me! Will mark you as brainiest!

shusha [124]

Answer:

Step-by-step explanation:

3 hrs to travel 45 miles downstream

4 hrs to travel 28 miles upstream

speed of boat in still water= s

speed of the current= c

s+c= 45/3= 15
s-c= 28/4=7

added up the 2 equations, we get:

2s= 22
s= 11 mph
c= 4 mph

6 0

3 years ago

Simply

Digiron [165]

Answer:

A.6^1/12

Step-by-step explanation:

3√6/4√6

when dividing the same base, subtract the powers.

(6^1/3)/(6^1/4)

6^(1/3-1/4)

6^(4-3)/12

6^1/12

option A is collect

5 0

3 years ago

Simplify the expression

yaroslaw [1]

$\bf ~~~~~~~~~~~~\textit{negative exponents}
\\\\
a^{-n} \implies \cfrac{1}{a^n}
\qquad \qquad
\cfrac{1}{a^n}\implies a^{-n}
\qquad \qquad 
a^n\implies \cfrac{1}{a^{-n}}
\\\\
-------------------------------\\\\
5^{-2}\div 5^4\implies \cfrac{5^{-2}}{5^4}\implies \cfrac{1}{5^25^4}\implies \cfrac{1}{5^{2+4}}\implies \cfrac{1}{5^6}\implies \cfrac{1}{15625}$

8 0

4 years ago

Determine the quadrant when the terminal side of the angle lies according to the following conditions: cos (t) < 0, csc (t) &

Bess [88]

Answer:

The angle is in the second quadrant.

Step-by-step explanation:

The cosecant of an angle is the same as the reciprocal of the sine of that angle. In other words, as long as $\sin (t) \ne 0$ ,

$\displaystyle \csc t = \frac{1}{\sin t}$ .

Therefore, $\csc(t) > 0$ is equivalent to $\sin (t) > 0$ .

Consider a unit circle centered at the origin. If the terminal side of angle $t$ intersects the unit circle at point $(x,\, y)$ , then

$\cos (t) = x$ , and
$\sin(t) = y$ .

For angle $t$ ,

$x = \cos(t) < 0$ , meaning that the intersection is to the left of the $y$ -axis.
$y = \sin(t) > 0$ , meaning that the intersection is above the $x$ -axis.

In other words, this intersection is above and to the left of the origin. That corresponds to second quadrant of the cartesian plane.

6 0

3 years ago