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Greeley [361]
3 years ago
9

Whenever a,x,y are positive integers, which of the following expressions is equivalent to x^ay^a

Mathematics
1 answer:
lilavasa [31]3 years ago
3 0

Answer:

{(xy)}^{a}

Step-by-step explanation:

when the exponent is equal, we can put the x and y together in a bracket and a as the Exponent of xy.

Hope I get your question~

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Samantha is making special edition hazelnut and almond chocolate boxes to give to her friends. It costs Samantha $15 to make one
Colt1911 [192]

Answer:

5

Step-by-step explanation:

6 0
3 years ago
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The scatter plot shows the number of customers in a restaurant for hours of the dinner services on two different Saturday nights
charle [14.2K]

A. The value y-intercept represent in the context of the problem is 50.

B. The slope of the line is -10.

C. The equation to represent the line is y= -10x+50.

D. The number of customers in the restaurant at 8:30pm is 35.

<u>Step-by-step explanation:</u>

The equation of the line is given by y=mx+c.

y is the number of customers and x is the hours.

7.00 p.m. is considered as 0.

To find the slope m =\frac{rise}{run}.

rise = y_{2}-y_{1}.

run = x_{2}-x_{1}.

From the graph, choose two points. Let us take (0,50) and (4,10).

m=\frac{-40}{4}.

m=-10.

∴The equation can be written as y= -10x+c.

To find the y-intercept value c, substitute any point.

Let us substitute(0,50) for instance,

50=0+c.

c=50.

The equation for the given graph is y= -10x+50.

To find the customers at the restaurant at 8.30 pm.

we know that x=0 at 7.00 pm,

∴ x=1.5 can be considered as 8.30 pm.

Substitute x=1.5 in the line equation.

y= -10(1.5)+50.

y= -15-50.

y= 35.

5 0
3 years ago
Two of the statements are true; one is a lie.
Temka [501]

Answer:

Statement 3

Step-by-step explanation:

∠GAF ≅ ∠TAE

Since, there is no relation between these angles,

Therefore, statement is False.

∠TAE and ∠FAH are complementary.

If the sum of the two angles is 90°, pair of angles is said to be complimentary angles.

Therefore, this statement is False.

∠TAF is obtuse.

Measure of obtuse angle is more than 90°

From the given picture, measure of ∠TAF = m∠TAH + m∠HAF

                                                                      = 90° + 50°

                                                                      = 140°

Here, m∠TAF > 90°

Therefore, ∠TAF is an obtuse angle.

Statement (3) is the correct statement.

8 0
3 years ago
53,806 in expanded form using exponents
Sholpan [36]
53.806= 5*10^5+3*10^4+8*10^3+6
4 0
3 years ago
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Find the probability of the following events , when a dice is thrown once:
Fudgin [204]

Answer:

Step-by-step explanation:

s a die is rolled once, therefore there are six possible outcomes, i.e., 1,2,3,4,5,6.

(a) Let A be an event ''getting a prime number''.

Favourable cases for a prime number are 2,3,5,

i.e., n(A)=3

Hence P(A)=n(A)n(S)=36=12

(b) Let A be an event ''getting a number between 3 and 6''.

Favourable cases for events A are 4 or 5.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(c) Let A be an event ''a number greater than 4''.

Favourable cases of events A are 5, 6.

i.e., n(A)=2

P(A)=n(A)n(S)=26=13

(d) Let A be the event of getting a number at most 4.

∴ A={1,2,3} ⇒ n(A)=4,n(S)=6

∴ Required probability =n(A)n(S)=42=23

(e) Let A be the event of getting a factor of 6.

∴ A={1,2,36} ⇒ n(A)=4,n(A)=6

∴ Required probability =46=23

(ii) Since, a pair of dice is thrown once, so there are 36 possible outcomes. i.e.,

(a) Let A be an event ''a total 6''. Favourable cases for a total of 6 are (2,4), (4,2), (3,3), (5,1), (1,5).

i.e., n(A)=5

Hence P(A)=n(A)n(S)=536

(b) Let A be an event ''a total of 10n. Favourable cases for total of 10 are (6,4), (4,6), (5,5).

i.e., n(A)=5

P(A)=n(A)n(S)=336=112

(c) Let A be an event ''the same number of the both the dice''. Favourable cases for same number on both dice are (1,1), (2,2), (3,3), (4,4), (5,5), (6,6).

i.e., n(A)=6

P(A)=n(A)n(S)=636=16

(d) Let A be an event ''of getting a total of 9''. Favourable cases for a total of 9 are (3,6), (6,3), (4,5), (5,4).

i.e., n(A)=4

P(A)=n(A)n(S)=436=19

(iii) We have, n(S) = 36

(a) Let A be an event ''a sum less than 7'' i.e., 2,3,4,5,6.

Favourable cases for a sum less than 7 ar

7 0
3 years ago
Read 2 more answers
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