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pochemuha
3 years ago
9

Which expression is tge simplest form of -(4x+y)+2(x-3y)​

Mathematics
2 answers:
Andre45 [30]3 years ago
5 0

Answer:

Step-by-step explanation:

-(4x+y)+2(x-3y)​ = -4x - y +2x - 6y

                         = -2x -7y

zloy xaker [14]3 years ago
3 0

Answer:

-2x - 5y

Step-by-step explanation:

-(4x+y)+2(x-3y)

First multiply 2 with (x-3y)

2 × (x-3y) = 2x - 6y

Now find the sum of this with -(4x+y) by adding/subtract like terms

2x - 6y - 4x - y = -2x - 5y

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The answer is choice C
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I am very confused please solve and explain.
e-lub [12.9K]

Answer:

c = \frac{b^2-R^2}{4a}

Step-by-step explanation:

Given

R= \sqrt{b^2-4ac}

Clear the radical by squaring both sides

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\frac{b^2-R^2}{4a} = c

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3 years ago
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Stephen says that the numbers 38 and 40 are relatively prime. Explain why he is incorrect in making this statement. (make a good
Paha777 [63]

Answer:

He is incorrect in this statement because 38 and 40 both have factors, other than 1 x itself. Prime numbers are numbers the only have 1 factor pair, and that is 1 x itself. Factors are the numbers you multiply to get the end result, and an example is 10x4=40. The factors of 40 are 8x5, 4x10, 2x20, and of course, 1x40. The factors of 38 are 2x19, and 1x38.

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2 years ago
If a function is derivable at a point it is also continous at that point explain why?
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3 years ago
What is the tan invers of 3i/-1-i​
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<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> )

<em>z</em> = 3<em>i</em> / (-1 - <em>i</em> ) × (-1 + <em>i</em> ) / (-1 + <em>i</em> )

<em>z</em> = (3<em>i</em> × (-1 + <em>i</em> )) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3<em>i</em> + 3<em>i</em> ²) / ((-1)² - <em>i</em> ²)

<em>z</em> = (-3 - 3<em>i </em>) / (1 - (-1))

<em>z</em> = (-3 - 3<em>i </em>) / 2

Note that this number lies in the third quadrant of the complex plane, where both Re(<em>z</em>) and Im(<em>z</em>) are negative. But arctan only returns angles between -<em>π</em>/2 and <em>π</em>/2. So we have

arg(<em>z</em>) = arctan((-3/2)/(-3/2)) - <em>π</em>

arg(<em>z</em>) = arctan(1) - <em>π</em>

arg(<em>z</em>) = <em>π</em>/4 - <em>π</em>

arg(<em>z</em>) = -3<em>π</em>/4

where I'm taking arg(<em>z</em>) to have a range of -<em>π</em> < arg(<em>z</em>) ≤ <em>π</em>.

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2 years ago
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