D (-4; -2)
C (1; 2)
M (x; y)
DM+MC=CD
CM:MD=1:3
M: x= x(C)-(x(C) - x(D))/4=1-(1-(-4))/4=1 - (6/4)=1 - 1,5= - 0,5
M: y=y(C)-(y(C) - y(D))/4=2-(2-(-2))/4=2 - (4/4)=2 - 1=1
M(x; y)=M( -0,5; 1)

8 0

4 years ago

PLEASE HELP I WILL GIVE BRAINALIST

OleMash [197]

Answer:

Step-by-step explanation:

If you multiply the feet with second you will get their speed

For example:

Moises: 15÷3 = 5 feet per sec

Xavier: 15÷2 = 7,5 feet per sec

-Then, you just need to compare them with the answer, and we have the last answer is D

3 0

3 years ago

What is 1/4+2/3 equal

Alexxandr [17]

Answer:

0.91666666666

Step-by-step explanation:

1/4 + 2/3 = 0.91666666666

3 0

3 years ago

Read 2 more answers

Sam Houston's Arms

OLga [1]

Answer:

The length of the statue's arm is<u> 26.22 ft.</u>

Step-by-step explanation:

Let the length of the statue's arm be 'x'.

Given:

Height of statue is, $H=67\ ft$

Height of male is, $h=5\ ft\ 9\ in=5\ ft+\frac{9}{12}\ ft=5+0.75=5.75\ ft$

Length of the male's arm is, $l=27\ in=\frac{27}{12}=2.25\ ft$

Now, as the size of Sam Houston's statue is proportional to that of an adult male, therefore, their heights and arm lengths will also be in proportion. So,

$\frac{H}{h}=\frac{x}{l}\\x=\frac{H}{h}\times l$

Now, plug in the given values and solve for 'x'.

$x=\frac{67}{5.75}\times 2.25\\x=26.22\ ft$

Therefore, the length of the statue's arm is 26.22 ft

7 0

3 years ago