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pav-90 [236]
3 years ago
14

How do you solve?3(t+4)-2(2t+3)=-4

Mathematics
2 answers:
shepuryov [24]3 years ago
8 0
3t+12-4t-6=-4
-t=-4+6-12
-t=-10
t=10
That's your answer.
Gnoma [55]3 years ago
8 0
3(t+4) - 2(2t+3) = -4
3t + 12 - 4t -12 = -4     ~step1: distribute both parenthesis
-t = -4                        ~step2: combine like terms (the 12s cancel each other)  
t=4                         ~step3: multiply each side by "-1" to rid of the - sign

hope this helped ! c:

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The level of nitrogen oxides (NOX) in the exhaust after 50,000 miles or fewer of driving of cars of a particular model varies No
Greeley [361]

Answer:

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.              

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.02 g/mi

Standard Deviation, σ = 0.01 g/mi

Sample size, n = 81

We are given that the distribution of  level of nitrogen oxides is a bell shaped distribution that is a normal distribution.

Standard error due to sampling:

=\dfrac{\sigma}{\sqrt{n}} = \dfrac{0.01}{\sqrt{81}} = 0.0011

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.01

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 0.02}{0.0011})=0.01  

= 1 -P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.01  

=P( z \leq \displaystyle\frac{x - 0.02}{0.0011})=0.99  

Calculation the value from standard normal z table, we have,  

\displaystyle\frac{x - 0.02}{0.0011} = -2.326\\\\x = 0.0174

For a level of 0.0174 or more of nitrogen oxide, the probability of fleet is 0.01.

5 0
2 years ago
A runner runs 8 miles in 92 minutes. What is the runners unit rate?
KiRa [710]

For this case, what we must do is calculate the speed of the runner.

We have then that the speed is given by:

v =\frac{d}{t}

Where,

d: distance

t: time

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V = 0.09 \frac{miles}{minutes}

Answer:

the runners unit rate is:

V = 0.09 \frac{miles}{minutes}

5 0
3 years ago
Read 2 more answers
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Roman55 [17]

Answer:

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Step-by-step explanation:

Put the numbers where the variables are and evaluate:

  F(3) = 2(3)^2 +1 = 19

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Then the desired sum is ...

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3 0
3 years ago
8. If3:8=c:56, the value of c will be
adelina 88 [10]

The scale for the second values is 56/8 = 7

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6 0
3 years ago
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Answer:

y = 52500(.91)^x

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Exponential functions are written y = ab^x where a is the starting point and b is the common ratio. We know the initial worth is 52500 and each year the worth decreases 9% of the original year, making it work 91% of the previous value.

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