Answer:
Step-by-step explanation:
13) x⁴-12x² +36
(a-b)² = a²-2ab+b²
a = x² ; b = 6
(x²)² - 2 * x² * 6 + 6² = (x² - 6)²
14) w⁴- 14w² - 32 = w⁴+ 2w² - 16w² - 32 = w² (w² + 2) - 16 (w²+2)
= (w² + 2) (w² -16 )
15) k³ + 7k² - 44k = k ( k² + 7k -44) = k ( k+11 ) ( k-4 )
16) 2a³ +28a²+96a =2a(a²+14a+48) = 2a(a+6)(a+8)
17) -x³ +4x² +21x = (-x) ( x² - 4x - 21) = (-x)(x-7)(x+3)
18) m⁶ - 7m⁴ -18m² = m² ( m⁴-7m²-18) = m² (m²-9)(m²+9)
= m² (m+1) (m-1)(m²+9)
19) 9y⁶ +6y⁴ + y²= y² ( 9y⁴+6y²+1) = y² (3y²+1)²
20) 8c⁴+10c² -3 = (4c +1)(2c-3)
Lil uzi vert said no sorry and it won’t work cause 5 + 5 is weird yk what I mean bro?
Step-by-step explanation:
<h3>Given</h3>
- Side 1: 3x² - 2x - 1
- Side 2: 9x + 2x² - 3
- Perimeter: 5x³ + 4x² - x - 3
<h3>Part A</h3>
Sum of side lengths 1 and 2
- 3x² - 2x - 1 + 9x + 2x² - 3 =
- 5x² + 7x - 4
<h3>Part B</h3>
The perimeter is the sum of all three sides.
<u>The length of the third side is</u>
- P - (side 1 + side 2) =
- 5x³ + 4x² - x - 3 - (5x² + 7x - 4) =
- 5x³ + 4x² - x - 3 - 5x² - 7x + 4 =
- 5x³ - x² - 8x + 1
Part A - addition
Part B - subtraction
There are six coins already in pocket, but let’s say we don’t know it.
We would figure it out by reversing the problem. Let’s start with twenty-nine. We would subtract 5, because we are reversing. Now we have 24. Now, let’s divide by four. We would get 6.
A simpler answer would be 29 - 5 [divided by] 4 = [answer]
You got to use the formula provided to solve the problem! Have confidence! you can do it!
