Answer:
Step-by-step explanation:
First answer is 4. Second answer is 3/5.
1. bc/3 + a/xy + 3/ab
= b^2cxya + 3a^2b + 9xy/3xyab
2. (5/3y) + 2y - 12
=11/3y - 2
3. ?
Hope this helps and right! :)) Good luck
The two number are 39 and 13
<em><u>Solution:</u></em>
Let the two numbers be "a" and "b"
Let the larger number be "a" and the smaller number be "b"
<em><u>Given that, sum of two numbers is 52</u></em>
a + b = 52 ---------- eqn 1
<em><u>One number is 3 times as large as the other number</u></em>
Larger number = 3 times smaller number
a = 3b -------- eqn 2
<em><u>Let us solve eqn 1and eqn 2</u></em>
<em><u>Substitute eqn 2 in eqn 1</u></em>
3b + b = 52
4b = 52
b = 13
<em><u>Substitute b = 13 in eqn 2</u></em>
a = 3(13)
a = 39
Thus the two number are 39 and 13
This answer is 272 I know because I did it vertically
