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3 years ago

I have done this for a million times and I always get this one wrong I need the correct answer

Mathematics

2 answers:

LenaWriter [7]3 years ago

6 0

Answer:

A, B, and D.

Step-by-step explanation:

HEY!! remember that if a number has ^2, it basically means it's multiplied by itself. for example:

5^2 = 5 x 5

aka, 25.

You can use this to check each of the answers in your formula, like this:

if x=6, then:

x^2 < 100

6 x 6 = 36

36 < 100

A is one of your correct answers!

Also remember, if you multiply a negative by a negative, it becomes positive.

-5 x -5 = 25

-10 x -10 = 100

drek231 [11]3 years ago

6 0

The answer to this is A, B, D.

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3 years ago

Let point L be between M and N on MN. Given that MN=31, ML= h-15 and LN = 2h-8. Find LN

MrRa [10]

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3 years ago

Intravenous fluid bags are filled by an automated filling machine. Assume that the fill volumes of the bags are independent, nor

iren2701 [21]

Answer:

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

$X \sim N(\mu,0.08)$

Where $\mu$ and $\sigma=0.08$

Since the distribution for X is normal then the we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error is given by:

$SE= \frac{0.08}{\sqrt{24}}= 0.0163$

8 0

3 years ago