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vivado [14]
2 years ago
7

Solve by using substitution. y=3x 2x+ 5y = 34​

Mathematics
2 answers:
klemol [59]2 years ago
8 0
If ur solving for x and y the answer is:

x=2 and y=6

my work below: (hope this helps!)

viktelen [127]2 years ago
4 0

Answer:

x= 3y

​x=− 25y+17

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2)
Alekssandra [29.7K]

Answer:

$39.68

Step-by-step explanation:

12.40÷2.4=4.96

4.96×8=39.68

4 0
2 years ago
HELP URGENT STEP FUNCTIONS!!!!!!! Used books cost $2.25 each. Which expression represents the total number of books that can be
irinina [24]

Answer:

A. \left \lfloor \frac{10}{2.25} \right \rfloor

Step-by-step explanation:

We are given,

The cost of one book = $2.25

Since, it takes $2.25 to buy 1 book.

The, for $10, we can get \frac{1}{2.25}\times 10 i.e. \frac{10}{2.25} = 4.44

Since, number of books cannot be in decimals.

So, the closest integer to 4.44 is 4.

Hence, we can buy 4 books from $10.

Now, according to the options:

A. \left \lfloor \frac{10}{2.25} \right \rfloor = \left \lfloor 4.44\right \rfloor = 4

B. \left \lceil \frac{10}{2.25} \right \rceil = \left \lceil 4.44 \right \rceil=5

C. \frac{10}{\left \lceil 2.25\right \rceil} =\frac{10}{3} =0.33

D. \frac{10}{\left \lfloor 2.25\right \rfloor} = \frac{10}{2} = 5

Hence, we see that from the options, A is correct.

3 0
2 years ago
Read 2 more answers
Solve this equation: 80 = 3y + 2y + 4 + 1.
Verdich [7]
Let us first write down the given equation.
80 = 3y + 2y + 4 + 1
80 = 5y + 5
80 - 5 = 5y
75 = 5y
Just reversing both sides we get
5y = 75
Now dividing both sides by 5 we get
y = 15
So the value of y is 15. I hope the procedure for solving the problem is clear to you. In future you can solve such problems with ease following the procedure described.



6 0
2 years ago
Read 2 more answers
Can someone help me please. -4-(4+3i)
olga2289 [7]
Your answer would be -11.

5 0
3 years ago
Which shows the expression below simplified? 0.00028 ÷ (7 × 10-4)
Katyanochek1 [597]
0.\underbrace{00028}_{\rightarrow5places}=28\times10^{-5}\\\\0.00028:(7\times10^{-4})=\dfrac{28\times10^{-5}}{7\times10^{-4}}=\dfrac{28}{7}\times\dfrac{10^{-5}}{10^{-4}}\\\\=4\times10^{-5-(-4)}=4\times10^{-5+4}=\huge\boxed{4\times10^{-1}}\leftarrow\boxed{b.}\\\\used\ \dfrac{a^n}{a^m}=a^{n-m}
6 0
3 years ago
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