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vivado [14]
3 years ago
7

Solve by using substitution. y=3x 2x+ 5y = 34​

Mathematics
2 answers:
klemol [59]3 years ago
8 0
If ur solving for x and y the answer is:

x=2 and y=6

my work below: (hope this helps!)

viktelen [127]3 years ago
4 0

Answer:

x= 3y

​x=− 25y+17

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100,388,073 Rounded to the nearest million
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Cooper earned $214.50 at his job when he worked for 13 hours. How much money did he earn each hour?
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$16.50

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The Taylor family want to go on holiday for two weeks. Hotel Return flight cost per person Hotel cost per person - 1 week Hotel
Harlamova29_29 [7]

240.70 x 4 = 962.80

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Please help. I'm stuck.
Bezzdna [24]
The root \sqrt{10} can be converted into the power 10^{ \frac{1}{2} }. Therefore we can rewrite the problem as (10^{ \frac{1}{2} } )^ {\frac{3}{4} x} and then follow the exponent rules about a power to a power, multiplying 1/2 and 3/4 together.

Thus the problem becomes 10^{\frac{3}{8}x}, which then can be turned into \sqrt[8]{10} ^{3x}, making the last option our answer.

4 0
4 years ago
Let P(t) be a population at time t. A simple population model supposes the rate of growth of the population is proportional to t
jeka94

Answer:

(a) \dfrac{dP}{dt} =k P(t)\\(b)P(t)=Ce^{kt}

(c)P(10)\approx 272

(ii)P(1000)\approx 26.88 \times 10^{44}\\

Step-by-step explanation:

(a)The rate of growth of the population is proportional to the population, this is written as:

\dfrac{dP}{dt} \propto P(t)\\$Introducing our proportionality constant, k\\ \dfrac{dP}{dt} =k P(t)

(b)

\dfrac{dP(t)}{P(t)} =k dt\\$Take the integral of both sides\\\int \dfrac{dP(t)}{P(t)} =\int k dt\\\ln P(t)=kt+C, $C a constant of integration\\Take the exponential of both sides\\e^{\ln P(t)}=e^{kt+C}\\P(t)=e^{kt}\cdot e^C  $, (Since e^C$ is a constant, we then have:)\\P(t)=Ce^{kt}

(c)

Suppose the net birthrate of the population is .1, and the initial population is 100.

k=0.1

P(0)=100

Substitution into P(t) gives:

100=Ce^{kX0}

C=100

Therefore:

P(t)=100e^{0.1t}

(i)When t=10

P(10)=100e^{0.1 \times 10}\\=271.8\\\approx 272

(ii)When t=1000

P(1000)=100e^{0.1 \times 1000}\\=26.88 \times 10^{44}\\

8 0
4 years ago
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