Answer:
f[g(1)] = 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 2x + 1
g(x) = 3x - 2
<u>Step 2: Find g(1)</u>
- Substitute in <em>x</em>: g(1) = 3(1) - 2
- Multiply: g(1) = 3 - 2
- Subtract: g(1) = 1
<u>Step 3: Find f[g(1)]</u>
- Substitute in g(1): f[g(1)] = 2(1) + 1
- Multiply: f[g(1)] = 2 + 1
- Add: f[g(1)] = 3
There are 31 days in january
I’m not quite sure but I think it could be c. 768
Pretty sure it’s the second one
