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nevsk [136]
3 years ago
5

Please helpppppppppppppppppppp

Mathematics
2 answers:
Sladkaya [172]3 years ago
6 0

Answer:

Answer A

Step-by-step explanation:

Sorry it is hard to give a Step-by-step explanation for this but the answer is a.

dimulka [17.4K]3 years ago
3 0

Answer:

It shall be D 60 grams

Step-by-step explanation:

Also can you give brainliest to all of your questions bc it really hard to get brainliest and it be really nice you can choose who i dont really care but just please do it it helps a lot :D

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Step-by-step explanation:

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3 years ago
24 + 0.44x = 19 + 1.69x
lys-0071 [83]

Answer:

if it is find the value of x her it is

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What is the range of the function graphed below?<br> A. 1_ B. -3 C. -2_ D. -3_
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Multiply these binomials.
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3 years ago
We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure
STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be h(t) = -16\cdot t^{2} + 128\cdot t + 320, the first and second derivatives are, respectively:

First Derivative

h'(t) = -32\cdot t +128

Second Derivative

h''(t) = -32

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

-32\cdot t +128 = 0

t = \frac{128}{32}\,s

t = 4\,s (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320

h(4\,s) = 576\,ft

The highest altitude that the object reaches is 576 feet.

6 0
3 years ago
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