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2 years ago

Solve the equation by finding the common multiple.

Mathematics

1 answer:

Monica [59]2 years ago

6 0

Answer:

1. 17/24

2. 1 1/8

3. 1 1/6

4. 1 5/24

5. 1. 1/4

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A block of wood has a mass of 120g and a volume of 200cm3. What is the density of the wood?

ozzi

Density=mass/volume
given mass=120g and volume=200cm3
density= $\frac{120g}{200cm^3}=\frac{3}{5} \space\ \frac{g}{cm^3}$ or abot 0.6

the density is $0.6 \space\ \frac{g}{cm^3}$

3 0

4 years ago

Read 2 more answers

Find the equation of the line that goes through the points (3,8) and (9,16).

Aneli [31]

Answer:

4x-3y+12=0 is required eqn

Step-by-step explanation:

Let, 3,8 be x1,y1

9,16 be x2,y2

Now,

Eqn of st.line is y-y1 = y2-y2/x2-x1 * (x-x1)

y-8 = 16-8/9-3 * (x-3)

y-8 = 4/3*(x-3)

3y-24 = 4x-12

4x-3y+12=0 is required eqn

3 0

3 years ago

Determine the point estimate of the population proportion and the margin of error for the following confidence interval.Lower bo

Kamila [148]

Answer: The point estimate of the population proportion is . 485.

The margin of error is 0.273.

Step-by-step explanation:

Confidence interval for population proportion(p):

sample proportion ± Margin of error

Given: Lower bound of confidence interval = 0.212

Upper bound = 0.758

⇒sample proportion - Margin of error=0.212 (i)

sample proportion + Margin of error= 0.758 (ii)

Adding (i) and (ii) , we get

2(sample proportion) =0.970

⇒ sample proportion = 0.970÷2= 0.485

Since sample proportion is the point estimate of the population proportion.

So, the point estimate of the population proportion= 0.485

Now put sample proportion =0.485 in (ii), we get

0.485+ Margin of error= 0.758

⇒ Margin of error= 0.758 - 0.485 =0.273

i.e. The margin of error is 0.273.

5 0

3 years ago

What is the area of this figure? A square with sides measuring 7 inches. A triangle attached to one side of the square gives the

slavikrds [6]

B)66.5in^2

The square is 49in^2 and the triangle has side lengths of 5 and 7 so the area is (5*7/2=17.5)
49+17.5=66.5

4 0

3 years ago

Read 2 more answers

The intensity I of light varies inversely as the square of the distance D from the source. If the intensity of illumination on a

zhenek [66]

Answer:

The intensity on a screen 70 ft from the light is 1.728 foot candle.

Step-by-step explanation:

Given that,

The magnitude of intensity $I$ of light varies inversely as the square of the magnitude of distance D from the source.

That is

$I\propto \frac{1}{D^2}$

Then,

$\frac{I_1}{I_2}=\frac{D_2^2}{D_1^2}$

Given that,

The magnitude of intensity of illumination on a screen 56 ft from a light is 2.7 foot-candle.

Here,

$I_1$ =2.7 foot-candle, $D_1$ = 56 ft

$I_2$ =?, $D_2$ = 70 ft.

$\frac{I_1}{I_2}=\frac{D_2^2}{D_1^2}$

$\Rightarrow \frac{2.7}{I_2}=\frac{70^2}{56^2}$

$\Rightarrow \frac{I_2}{2.7}=\frac{56^2}{70^2}$

$\Rightarrow {I_2}=\frac{56^2\times 2.7}{70^2}$

$\Rightarrow {I_2}=1.728$ foot-candle

The intensity on a screen 70 ft from the light is 1.728 foot candle.

3 0

4 years ago