HELPP!! I am just so unsure about this problem. select EACH correct answer. Expertise please!

Mathematics

2 answers:

Ivahew [28]4 years ago

7 0

K(x) = (1/4)^x

(1,4) when x = 1, k(1) = (1/4)^1 = 1/4....FALSE
(3, 1/64) when x = 3, k(3) = (1/4)^3 = 1/64....TRUE
(-1,4) when x = -1, k(-1) = (1/4)^-1 = 4....TRUE
(0, 1/4) when x = 0, k(0) = (1/4)^0 = 1....FALSE

answer
(3, 1/64)
(-1,4)

adell [148]4 years ago

5 0

I am sure it is (1,4) hope this helps

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tatiyna

Answer:

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Step-by-step explanation:

4x-12 = x+7

4x-12+12 = x+7+12

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And if we substitute the value of x into the equation 4x-12 = x+7,

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solniwko [45]

A = 133; b = 31; c = 82; d = 64.
Opposite angles in an inscribed quadrilateral are supplementary; this means that d + 116 = 180. Subtracting 116 from both sides, we have d = 64.

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Inscribed angles are equal to 1/2 the measure of the intercepted arc. Using this, we have

116 = 1/2(a+99)

Multiplying both sides by 2, we have
232 = a+99

Subtract 99 from both sides:
232 - 99 = a + 99 - 99
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We also have that
82 = 1/2(133+b)

Multiplying both sides by 2, we have:
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Tcecarenko [31]

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Step-by-step explanation:

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