Question

Please help me with this! Picture is provided and only answer is you know it!

Answer 1

Answer:

Option A

Step-by-step explanation:

Number of components assembled by the new employee per day,

N(t) = $\frac{50t}{t+4}$

Number of components assembled by the experienced employee per day,

E(t) = $\frac{70t}{t+3}$

Difference in number of components assembled per day by experienced ane new employee

D(t)= E(t) - N(t)

D(t) = $\frac{70t}{t+3}-\frac{50t}{t+4}$

      = $\frac{70t(t+4)-50t(t+3)}{(t+3)(t+4)}$

      = $\frac{70t^2+280t-50t^2-150t}{(t+3)(t+4)}$

      = $\frac{20t^2+130t}{(t+3)(t+4)}$

      = $\frac{10t(2t+13)}{(t+4)(t+3)}$

Therefore, Option A will be the answer.