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Bumek [7]
3 years ago
9

Select the letter of the correct answer. A museum in South Africa uses paintings of right-angled triangles to teach children abo

ut the Pythagorean Theorem: A squared + B squared = C squared Let's say that A = 4 and B = 3. Based on the theorem, what is the value of C squared? Choose the correct expression. A 42+
32 B (4 x 3)2 C (4 + 3)2 D 4 + 3 ​

Mathematics
1 answer:
VikaD [51]3 years ago
5 0
The answer is C I think
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The explicit formula for the nth term of an arithmetic sequence is an = a1 + (n - 1) • d. What is the simple formula correspondi
BlackZzzverrR [31]
= -10 + (n - 1)*4
= -10 + 4n - 4
= 4n - 14
5 0
3 years ago
Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the accou
storchak [24]

Hello!

Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years

Data:

P = 35000

r = 4% = 0,04

n = 4

t = 5

P' = ?

I = ?  

We have the following compound interest formula

P' = P*(1+\dfrac{r}{n})^{nt}

P' = 35000*(1+\frac{0,04}{4})^{4*5}

P' = 35000*(1+0,01)^{20}

P' = 35000*(1,01)^{20}

P' = 35000*(1.22019003995...)

P' \approx 42,706.66

So the new principal P' after 5 years is approximately $42,706.66.  

Subtracting the original principal from this amount gives the amount of interest received:

P' - P = I

42,706.66 - 35000 = \boxed{\boxed{7,706.66}}\end{array}}\qquad\checkmark

________________________

I Hope this helps, greetings ... Dexteright02! =)

4 0
3 years ago
What is the answer and work for these attached below
GrogVix [38]
-4(-5-b)=1/3(b+16) Multiply both sides by 3 to get rid of the fraction
-12(-5-b)=b+16  distribute the -12 to get rid of the parenthesis 
60+12b=b+16  get the b on the left side and non b values to the right side
11b=-44 solve for b
b=-44/11 simplify the fraction
b=-4

3/5(t+18)=-3(2-t)   multiply both sides by 5/3 to get rid of thefraction
t+18=-5(2-t)   distribute the -5 to get rid of the parenthises
t+18=-10+5t  get the t to the left side and non t values to the right
-4t=-28  solve for t
t=7
5 0
3 years ago
a sequence starts a 200 and 30 is subtracted each time 200,170,140 what are the first two numbers in the sequence that are kess
Snowcat [4.5K]
<h3>Answer:  -10 and -40</h3>

===============================================================

Explanation:

a = 200 = first term

d = -30 = common difference

Tn = nth term

Tn = a + d(n-1)

Tn = 200 + (-30)(n-1)

Tn = 200 - 30n + 30

Tn = -30n + 230

Set Tn less than 0 and isolate n

Tn < 0

-30n + 230 < 0

230 < 30n

30n > 230

n > 230/30

n > 7.667 approximately

Rounding up to the nearest whole number gets us n \ge 8

So Tn starts to turn negative when n = 8

We can see that,

Tn = -30n + 230

T7 = -30*7 + 230

T7 = 20

and

Tn = -30n + 230

T8 = -30*8 + 230

T8 = -10 is the 8th term

and lastly

Tn = -30n + 230

T9 = -30*9 + 230

T9 = -40 is the ninth term

Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.

5 0
3 years ago
Read 2 more answers
In a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Interne
Dvinal [7]

Answer:

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

Step-by-step explanation:

Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

H_0: \bar x =12.7\\H_a: \bar x >12,7

(Right tailed test at 5% level)

Mean difference = 0.2

Std error = \frac{6}{\sqrt{1000} } \\=0.1897

Z statistic = 1.0540

p value = 0.145941

since p >alpha we do not reject H0.

b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.

5 0
3 years ago
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