Hello!
Lynne invested 35,000 into an account earning 4% annual interest compounded quarterly she makes no other deposits into the account and does not withdraw any money. What is the balance of Lynne's account in 5years
Data:
P = 35000
r = 4% = 0,04
n = 4
t = 5
P' = ?
I = ?
We have the following compound interest formula





So the new principal P' after 5 years is approximately $42,706.66.
Subtracting the original principal from this amount gives the amount of interest received:


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I Hope this helps, greetings ... Dexteright02! =)
-4(-5-b)=1/3(b+16) Multiply both sides by 3 to get rid of the fraction
-12(-5-b)=b+16 distribute the -12 to get rid of the parenthesis
60+12b=b+16 get the b on the left side and non b values to the right side
11b=-44 solve for b
b=-44/11 simplify the fraction
b=-4
3/5(t+18)=-3(2-t) multiply both sides by 5/3 to get rid of thefraction
t+18=-5(2-t) distribute the -5 to get rid of the parenthises
t+18=-10+5t get the t to the left side and non t values to the right
-4t=-28 solve for t
t=7
<h3>
Answer: -10 and -40</h3>
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Explanation:
a = 200 = first term
d = -30 = common difference
Tn = nth term
Tn = a + d(n-1)
Tn = 200 + (-30)(n-1)
Tn = 200 - 30n + 30
Tn = -30n + 230
Set Tn less than 0 and isolate n
Tn < 0
-30n + 230 < 0
230 < 30n
30n > 230
n > 230/30
n > 7.667 approximately
Rounding up to the nearest whole number gets us 
So Tn starts to turn negative when n = 8
We can see that,
Tn = -30n + 230
T7 = -30*7 + 230
T7 = 20
and
Tn = -30n + 230
T8 = -30*8 + 230
T8 = -10 is the 8th term
and lastly
Tn = -30n + 230
T9 = -30*9 + 230
T9 = -40 is the ninth term
Or once you determine that T7 = 20, you subtract 30 from it to get 20-30 = -10 which is the value of T8. Then T9 = -40 because -10-30 = -40.
Answer:
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.
Step-by-step explanation:
Given that in a study of computer use, 1000 randomly selected Canadian Internet users were asked how much time they spend using the Internet in a typical week. The mean of the sample observations was 12.9 hours.

(Right tailed test at 5% level)
Mean difference = 0.2
Std error = 
Z statistic = 1.0540
p value = 0.145941
since p >alpha we do not reject H0.
b. Do not reject H0. We do not have convincing evidence that the mean weekly time spent using the Internet by Canadians is greater than 12.7 hours.