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Savatey [412]
3 years ago
9

How many outcome sequences are possible when a die is rolled 4 times where we say for instance that the outcome is 3 4 3 1 if th

e first roll landed on 3 the second on 4 the third on 3 and the fourth on 1
Mathematics
1 answer:
STatiana [176]3 years ago
3 0

Answer:

the possible outcome sequences when a die is rolled 4 times is 1296

Step-by-step explanation:

 Given the data in the question;

a die is rolled 4 times

and outcomes are { 3, 4, 3, 1 }

we know that; possible number of outcomes on a die is n = 6{ 1,2,3,4,5,6 }

Now when we roll a die lets say, r times

then the total number of possible outcomes will be;

N = n^r

given that; r = 4

Hence if we roll a die 4 times;

Total number of possible outcome N = 6⁴

N = 1296

Therefore, the possible outcome sequences when a die is rolled 4 times is 1296

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Answer:

statement is TRUE  

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Step-by-step explanation:

(a)  

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So, in computing a definite integral of a linear function, the approximated value occurred by using Trapezoidal Rule is same as the area of the region.  Thus, the value of the definite integral of a linear function is exact, by using the Trapezoidal Rule.  

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(b) Recollect that for each rule of both the midpoint and trapezoidal rules, the number of sub-internals, n increases by a factor of a. then the error decreases by a factor of a^2.  

So, for the midpoint rule, the number of sub-intervals, n is increased by a factor of 3, then the error is decreased by a factor of 32 = 9, not 8. Therefore, the statement is FALSE  

(c) Recollect that for each rule of both the midpoint and trapezoidal rules, the number of sub-internals, n increases by a factor of a. then the error decreases by a factor of a^2.  

So, for the trapezoidal rule, the number of sub-internals, n is increased by a factor of 4. then the error is decreased by a factor of 42 = 16  

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3 0
3 years ago
Please help me with this !:(
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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