Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form 
is equal to
where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to
if 
----> the <u>quadratic equation</u> has two <u>real roots</u>
if 
----> the <u>quadratic equation</u> has one <u>real root</u>
if 
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
The answer is A !!!!!!!!
the two segments AD and AB are equal therefore if you make the two equal to each other you will get the answer:
<span>x^2+2=11 then you subtract two to put x squared on the side by itself
</span>then you have <span>x^2=9
then all you have to do is take the square root of 9 and </span><span>x^2 and you get x=3
thefore the answer is A</span>
Answer:
first do 58-4 which is 54 then do 54/ 9 which is 6 so the number is 6
To solve for C, you have to get both of the numbers with a C on the same side. So, subtract the 5c from the right side onto the left side.
Then, divide by 3 on each side.
So, c = 7.
