Given: In the given figure, there are two equilateral triangles having side 50 yards each and two sectors of radius (r) = 50 yards each with the sector angle θ = 120°
To Find: The length of the park's boundary to the nearest yard.
Calculation:
The length of the park's boundary (P) = 2× side of equilateral triangle + 2 × length of the arc
or, (P) = 2× 50 yards + 2× (2πr) ( θ ÷360°)
or, (P) = 2× 50 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 2× (2×3.14× 50 yards) ( 120° ÷360°)
or, (P) = 100 yards + 209.33 yards
or, (P) = 309.33 yards ≈309 yards
Hence, the option D:309 yards is the correct option.
Answer:
6
Step-by-step explanation:
sorry if it wrong
Answer:
• The function is a linear function
• The function changes at a constant rate
Step-by-step explanation:
A graph of the function shows it to be a straight line (linear function). Such a function always changes at a constant rate. The line goes downward to the right, so the function is a decreasing function.
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"changes at a constant rate" and "linear function" are two different ways of saying the same thing: the graph of the function is a straight line.
(2y+3)(3y^2+4y+5)
so u just multiply all the things from different brackets.
2y*3y^2 = 6y^3
2y*4y = 8y^2
2y*2 = 4y
3*3y^2 = 9y^2
3*4y = 12y
3*5 = 15
so 6y^3+8y^2+4y+9y^2+12y+15
thats the answer BUT u need to collect the like terms, otherwise u probably wont get full marks on the question, so:
6y^3+17y^2+16y+15
i hope this helps :)
someone correct me if im wrong
