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sammy [17]
3 years ago
14

The perimeter of triangle ABC is 32 find the lengths of AC and AB​

Mathematics
1 answer:
Nutka1998 [239]3 years ago
6 0

The lengths of AC and AB​ are each 10.6 units.

<u>Step-by-step explanation</u>:

Perimeter of a triangle = Sum of all the three sides of a triangle

  • Perimeter = 3a
  • where, a is the length of the each sides of a triangle.

⇒ 32 = 3a

⇒ a = 32/3

⇒ a = 10.6

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Mekhanik [1.2K]
z = -11

Steps:
8z+12 = 5z-21
Subtract 12 from both sides
8z+12-12 = 5z-21-12
Simplify
8z = 5z-33
Subtract 5z from both sides
8z-5z = 5z-33-5z
Simplify
3z = -33
Divide both sides by 3
3z/3 = -33/3
Simplify
z = -11

Hope this helps you! (:
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2 years ago
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egoroff_w [7]

Answer:

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Step-by-step explanation:

\begin{array}{cc}\text{Mathematical expression}&\text{Translation}\\ \\xy&\text{The product of two numbers}\\ \\\dfrac{x}{y}&x\text{ divided by }y\\ \\x-y&x\text{ minus }y\\ \\x+y&\text{the sum of }x\text{ and }y\\ \\y-x&x\text{ subtracted from }y\\ \\y:x&y\text{ divided by } x\\ \\x+y=6&\text{the sum of two numbers is 6}\\ \\xy=6&\text{the product of two numbers is 6}\\ \\6x=y&\text{6 times a number equals }y\\ \\y=x-6&\text{6 less than a number is }y\end{array}

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Answer:

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