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GalinKa [24]
3 years ago
8

Difference between absolute atomic mass and relative atomic mass with example

Chemistry
1 answer:
Harman [31]3 years ago
5 0

“Atomic mass” is relative to the isotope carbon-12 weighing exactly 12 atomic mass units. Therefore “atomic mass” is precisely the same as “relative atomic mass.”

Two further points:

First, atomic mass as stated on the periodic table is a average of the masses of an element’s naturally-occurring isotopes, weighted by their abundance. This is because atomic mass as normally used is a bulk property: we weigh out many trillions of atoms at a time, because we usually deal in macroscopic quantities. And that means that an average mass is more useful to us.

Second, all masses are relative masses (until the new, physical-constant-based kilogram comes online; and arguably even then). We mass something by comparing it to some standard of reference: until later this year, that something is a chunk of alloy in Paris, France. When the new standard comes into use, we will be comparing the kilogram’s gravitational mass to the strength of the electromagnetic force.

But that’s kind of trivial; it just stems from the fact that any and every measurement is a comparison to something else.

Edit: IUPAC, the world’s premier organization for the imposition of picky definitions that most people never need to use, has the following:

Atomic mass is the mass of a single atom; the unit is the Dalton or unified atomic mass unit. (I would use “isotopic mass” to specify the mass of a particular atom, but that’s not sanctioned by IUPAC.)

Relative atomic mass is the measured average mass of all atoms of a particular element in a particular sample. To make it unitless, it’s divided by the value of the unified atomic mass unit.

Standard atomic weight is the value you read off of the periodic table; it’s an Earth-based average over many samples, of experimental values of the relative atomic mass. Values are promulgated by the IUPAC Commission on Atomic Weights and Isotopic Abundances, and are revised every two years.

Most chemists refer to standard atomic weight as “atomic mass” or “atomic weight” and get on with their lives.

The unified atomic mass unit is 1/12 of the mass of an atom of carbon-12. It is sometimes called the Dalton.

Definitions taken from the IUPAC Gold Book.

As far as I can tell, relative atomic masses and standard atomic weights are made unitless so that they can be used with any convenient macroscopic mass unit to determine correct proportions for a desired chemical reaction.

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Is this a mole question
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A substance has twice the number of particles as 12 grams of carbon-12. How many
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Answer:

D)2.0

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Also, it is the number of particles in exactly 12.000 g of isotope carbon 12.

Avogadro constant:-

N_a=6.023\times 10^{23}

Thus,

Number of particles as 12 grams of carbon-12 constitutes 1 mole

<u>Twice the number of particles as 12 grams of carbon-12 constitutes 1*2 mole</u>

Thus, moles in the substance = 2.0 moles

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3 years ago
During a laboratory experiment you discover that an enzyme-catalyzed reaction has a delta G of -20 kcal/mol. If you double the a
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Answer:

-20 kcal/mol

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In a reaction, enzymes reduces the energy of activation, but they have no effect on the Gibb's free energy of reaction. The free energy of the product is the same as it would be without the enzyme. Thus, the enzyme does not affect the free energy of the reaction. Mathematically

Gibb free energy = Enthalpy - temperature x change in entropy

Note that from the relation above, enzyme is not a factor nor is activation energy a factor.

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In addition to mass balance, oxidation-reduction reactions must be balanced such that the number of electrons lost in the oxidat
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Answer:

Part A: (1, 1, 4, 1, 1, 1)

Part B: (2, 6, 4, 2, 3, 8)

Explanation:

Redox reactions can be balanced using the half-reaction method. It has the following steps:

  1. We write both half-reactions (reduction and oxidation)
  2. We balance the masses using H⁺ and H₂O in acidic media or OH⁻ and H₂O in basic media.
  3. We add electrons to balance electrically the half-reaction
  4. We multiply the half-reaction by numbers to make sure the number of electrons gained and lost are the same.
  5. We add both half-reactions and take the numbers to the general equation.

<em>Acidic solution</em>

SO₄²⁻(aq) + Sn²⁺(aq) + X ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + Y

1.

Reduction: SO₄²⁻ ⇒ SO₃²⁻

Oxidation: Sn²⁺ ⇒ Sn⁴⁺

2.

2 H⁺ + SO₄²⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺

3.

2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O

Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻

4.

1 x [2 H⁺ + SO₄²⁻ + 2 e⁻ ⇒ SO₃²⁻ + H₂O]

1 x [Sn²⁺ ⇒ Sn⁴⁺ + 2 e⁻]

5.

2 H⁺ + SO₄²⁻ + 2 e⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺ + 2 e⁻

2 H⁺ + SO₄²⁻ + Sn²⁺ ⇄ SO₃²⁻ + H₂O + Sn⁴⁺

Taking this to the general equation:

SO₄²⁻(aq) + Sn²⁺(aq) + 2 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

Since H⁺ are spectator ions, they are not balanced automatically through this method and we have to balance them manually. In this case, we need to add 2 more H⁺ to the left.

SO₄²⁻(aq) + Sn²⁺(aq) + 4 H⁺(aq) ⇄ H₂SO₃(aq) + Sn⁴⁺(aq) + H₂O(l)

<em>Basic solution</em>

MnO₄⁻(aq) + F⁻(aq) + X ⇄ MnO₂(s) + F₂(aq) + Y

1.

Reduction: MnO₄⁻ ⇒ MnO₂

Oxidation: F⁻ ⇒ F₂

2.

2 H₂O + MnO₄⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂

3.

2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻

2 F⁻ ⇒ F₂ + 2 e⁻

4.

2 × (2 H₂O + MnO₄⁻ + 3 e⁻ ⇒ MnO₂ + 4 OH⁻)

3 × (2 F⁻ ⇒ F₂ + 2 e⁻)

5.

4 H₂O + 2 MnO₄⁻ + 6 e⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂ + 6 e⁻

4 H₂O + 2 MnO₄⁻ + 6 F⁻ ⇄ 2 MnO₂ + 8 OH⁻ + 3 F₂

Taking this to the general equation:

2 MnO₄⁻(aq) + 6 F⁻(aq) + 4 H₂O ⇄ 2 MnO₂(s) + 3 F₂(aq) + 8 OH⁻

This equation is balanced.

6 0
3 years ago
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