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klasskru [66]
3 years ago
10

A 7.50 liter sealed jar at 18 degrees C contains 0.125 moles of oxygen and 0,125 moles of nitrogen gas. What is the pressure in

the container?
Chemistry
1 answer:
LiRa [457]3 years ago
6 0
PV = nRT —> P = nRT/V
n = 0.250 moles of gas
R = 0.08206 L atm / mol K
T = 18 + 273 = 291 K
V = 7.50 L

P = (0.250)(0.08206)(291)/(7.50) = 7.96 atm
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Ecell = 0.60 - \frac{0.0591 }{6} \frac{log( 1.20)^2}{ ( 0.200)^3}

Ecell = 0.577 V

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