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Tanya [424]
3 years ago
11

The isosceles triangle shown has a base of 4 y + 2 and a perimeter of 6 y + 12 .  Which expression represents the length of 1 o

f the triangle's legs?
Mathematics
1 answer:
liberstina [14]3 years ago
4 0

Answer:

The expression that represents the length of 1 of the triangle's legs is y + 5

Step-by-step explanation:

An isosceles triangle has two sides equal which are the triangle legs. Let b represent the base of the triangle and l represent one of the triangle's legs. Then, the perimeter, P is given by

P = l + l + b

i.e P = 2l + b

From the question, P = 6y + 12 and b = 4y +2

∴ 6y + 12 = 2l + 4y + 2

6y - 4y + 12 - 2 = 2l

2y + 10 = 2l

∴ 2l = 2y + 10

Then,

l = (2y+10)/2

l = y + 5

Hence, the expression that represents the length of 1 of the triangle's legs is y + 5  

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Step-by-step explanation:

Given

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Required

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When multiplied by 4 - 3i, the result is as follows;.

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Expand

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Result = 16 - 12i + 3i(4 - 3i)

Open the second bracket

Result = 16 - 12i + 12i - 3i * 3i

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Hence, when the denominator of the fraction is multiplied by 4 - 3i, the result is 25

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