The equation of a straight like in the from y – y1 =m(x-x1) where m is the slope of the like and (x1 , y1) are the coordinates of a given point on the line — compare slope intercept form.
Sorry i really need points
The answer C make more sense.
Since x=-3y+5, substitute x for -3y+5.
2(-3y+5)+8y=4
Distribute.
-6y+10+8y= 4
2y+10= 4
Subtract 10 on both sides.
2y=-6
Divide by 2.
y=-3
Plug in y=-3.
x=-3(-3)+5
x= 9+5
x=14
(14,-3)
We can check this.
2(14)+8(-3)=4
28-24=4
4=4 <== this works
I hope this helps!
~kaikers
