ANSWER
C. If it is not night, then the street lights will not come on.
EXPLANATION
The given statement is
"If it is night, then the street lights will come on"
Given the statement,
"If p, then q",
then the inverse of this statement is
"If it is not night,then the street lights will not come on"
"If not p, then not q"
The correct choice is C.
Answer:
The combination 9 mm, 6mm, 5mm will not form a triangle.
9 +6 = 15 > 5
6+5= 11 < 9
9+5 =14 > 6
Explanation :
because the side length of triangle does not obey triangle inequality theorem.
The triangle inequality theorem:
The sum of the lengths of any two sides of a triangle is greater than the length of the third side.
Answer:
29°, 58°, and 93°
Step-by-step explanation:
If the angles opposite are equal, the sides are equal. In order to have three different side lengths, you must have <em>three different angles</em>.
Let h = height of the box,
x = side length of the base.
Volume of the box is

.
So

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is


The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

![4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86](https://tex.z-dn.net/?f=%204x%20%3D%20%5Cfrac%7B460%7D%7B%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%204x%5E%7B3%7D%20%3D%20460%20%20%5C%5C%20x%5E%7B3%7D%20%3D%20115%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B115%7D%20%3D%204.86%20)
Then

So the box is 4.86 in. wide and 4.87 in. high.