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Leto [7]
2 years ago
11

Find the product. Pls help lol

Mathematics
2 answers:
elena-s [515]2 years ago
7 0

Answer:

6 {x}^{3}  + 5 {x}^{2}  - 16x + 15

Step-by-step explanation:

6 {x}^{3}  - 9 {x}^{2}  + 4 {x}^{2}  - 6x  - 10 x+ 15 \\ 6 {x}^{3}  + 5 {x}^{2}  - 16x + 15

lions [1.4K]2 years ago
3 0

Use the distributive property: a (b + c) = ab + ac

(3x² + 2x - 5) (2x - 3) = 3x² (2x - 3) + 2x (2x - 3) - 5 (2x - 3)

... = (6x³ - 9x²) + (4x² - 6x) + (-10x + 15)

... = 6x³ - 5x² - 16x + 15

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Consider a normally distributed data set with a mean of 75 and a standard deviation of 5. If
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Answer:

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Step-by-step explanation:

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3 0
3 years ago
Do you know what 2/9 x 3 is?
ohaa [14]

Answer:

answer =  \frac{2}{3}

\frac{2}{9}  \times  \frac{3}{1}  \\   =  \frac{6}{9}  =  \frac{2}{3}

7 0
3 years ago
Read 2 more answers
Help me pleasse th sdjkhhjdas
storchak [24]

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<h3>7.75% × $6 ÷ 100</h3><h3>= 0.465 × 2</h3><h3>= 0.93%</h3><h3><u>Andre Saved 0.93% In Total At The Sale</u></h3>

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8 0
2 years ago
Read 2 more answers
Let f(x)=x+a/x+b such that f(f(1)=0 &amp; f(2)=-3 then a&amp;b resctivily are.
Yuliya22 [10]

Answer:

The value of a = - 1  ,   And b = \frac{ - 7 }{3}    

Step-by-step explanation:

Given as :

Function f(x) = \frac{(x + a)}{(x + b)}

And f(f(1)) = 0     And f(2) = - 3

Now For , x = 2 , y = - 3

I.e  f(2) = \frac{(2 + a)}{(2 + b)}

or,  - 3 = \frac{(2 + a)}{(2 + b)}

I.e 2 + a = - 6 - 3b

Or, a + 3b = - 8               ....... 1

Again  f(f(1)) = 0

So,  \frac{(1 + a)}{(1 + b)} = 0

Or,  1 + a = 0

∴    a = - 1

So , put htis value of a i n eq 1 , we get value of  b

So , - 1 + 3b = - 8

Or,   3b = - 7

∴       b = \frac{ - 7 }{3}

Hence The value of a = - 1  ,   And b = \frac{ - 7 }{3}    Answer

3 0
3 years ago
I don’t know the answer to this question.
serious [3.7K]

6×(1×5)=(6×1)×5

6×5=6×5

30=30

Always do the brackets first.

Follow BEDMAS

B = Brackets

E = Exponent

D = Division

M = multiplication

A = Addition

S = Substruction

3 0
3 years ago
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