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TEA [102]
3 years ago
11

Biology homework please help

Biology
1 answer:
ludmilkaskok [199]3 years ago
7 0

Answer:

muscles

ribs

lungs

bronchioles

alveoli

diffuses

leaves

exchange

Explanation:

Your diaphragm, and <u>muscles</u> between your <u>ribs</u>, make air move in and out of your <u>lungs</u>. It travels through the trachea, bronchi, and <u>bronchioles </u>to <u>alveoli</u>. In the alveoli, oxygen <u>diffuses</u> into the blood and carbon dioxide<u> leaves</u>. This is gas <u>exchange</u>.

<em>Air enters the lungs and leaves it as a result of the relaxation and contraction of the diaphragm and the muscles between the ribs. When both the muscles and the diaphragm relax, air enters from the trachea and travels through the bronchi and the bronchioles to the alveoli, where the oxygen in the air diffuses into the blood and carbon dioxide diffuse in the opposite direction. The entire process is known as gas exchange.</em>

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if the ratio of the ages of kisii and esinam is 3:5 and that of Esinam and Larry is 3:5 and the sum of the ages of all three is
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Answer:

The age difference between the oldest and the youngest is 48.

Explanation:

Given the following data;

The ratio of the ages of Kisii (K) and Esinam (E) is 3:5.

The ratio of the ages of Esinam (E) and Larry (L) is 3:5.

The sum of the ages of all three is 147.

Since the age of Esinam is common in both ratios, we find the lowest common multiple (LCM);

LCM of 3,5 = 15.

Hence, the ratio of the three ages is now;

K:E:L = 9:15:25

Let their ages be denoted by x;

K:E:L = 9x:15x:25x

The sum of all three ages is;

9x + 15x + 25x = 147

49x = 147

x = 147/49

x = 3.

To find the age difference between the oldest and the youngest;

The oldest is Esinam = 25x

The youngest is Kisii = 9x

Therefore, 25x - 9x = 16x

Substituting the value of x, we have;

x = 3; 16x = 16(3) = 48.

The age difference between the oldest and the youngest is 48.

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