Answer:
1 hour
Step-by-step explanation:
Lea's speed = 22km/hr
Trevon's speed = 43km/hr in a direction opposite Lea's
How long does Trevon needs to drive before they are 65km apart.
Note : both took at the same time and in opposite direction.
Recall : speed = distance / time
Distance = speed * time
Distance between them = 65km
Let Trevon's distance = D2 = 43 * t
Lea's distance = D1 = 22 * t
t is the same since they both left at the same time.
D2 + D1 = 65
43t + 22t = 65
65t = 65
t = 65/65
t = 1 hour
Answer:
Step-by-step explanation: The simplification calculator allows you to take a simple or complex expression and simplify and reduce the expression to it's simplest form.
<span> If all numbers are greater than zero and no repeated numbers exist these are the 5 possible combinations:
1 + 2 + 8
1 + 3 + 7
1 + 4 + 6
2 + 3 + 6
2 + 4 + 5.
If one number is allowed to be zero and no repeated numbers exist these are 5 combinations:
</span><span> 0 + 11
1 + 1 + 9
2 + 2 + 7
3 + 3 + 5
4 + 4 + 3
5 + 5 + 1
</span><span>
Hope this helps
</span>
This is my kinda language.
fifty four= 54
less than: -
one-third: /3
number: n
n/3-54 <=== the expression
I hope this helps!
~kaikers